Chapter 2: Problem 140
Find the volume generated when the region between the curves is rotated around the given axis. \(y=3-x, y=0, x=0,\) and \(x=2\) rotated around the \(y\) -axis.
Short Answer
Expert verified
The volume is \(\frac{26\pi}{3}\).
Step by step solution
01
Understand the Problem
The region is bounded by the curves: \(y=3-x\), the x-axis \(y=0\), and the vertical lines \(x=0\) and \(x=2\). We are to find the volume generated when this region is rotated around the y-axis.
02
Set Up the Integral
When rotating around the y-axis, consider horizontal slices (washers). In terms of y, the bounds become from \(y=0\) to \(y=2\) because on the line \(y=3-x\), \(x\) ranges from \(0\) to \(2\). The equation \(x = 3 - y\) (rearrange \(y = 3-x\)) describes the curve in terms of \(y\).
03
Write the Volume Element
The formula for the volume element when rotated around the y-axis using the washer method is: \[ dV = \pi [R(y)]^2 \, dy \]where \(R(y)\) is the radius of the washer, given by the x-coordinate \(x = 3 - y\) of the boundary line, since \(x\) is the distance from the y-axis.
04
Determine the Volume Integral
The volume integral is set up from the lower to upper bounds of \(y\), which are from y = 0 to y = 2:\[ V = \pi \int_{0}^{2} (3-y)^2 \, dy \]
05
Evaluate the Integral
First expand \((3-y)^2\) to \(9 - 6y + y^2\). Integrate each part:\[ \int (9 - 6y + y^2) \, dy = 9y - 3y^2 + \frac{1}{3}y^3 \] Evaluate from 0 to 2:\[ V = \pi \left[ (9(2) - 3(2)^2 + \frac{1}{3}(2)^3) - (9(0) - 3(0)^2 + \frac{1}{3}(0)^3) \right] \]
06
Calculate Numerically
Substitute to find the numerical value:\[ V = \pi \left[ 18 - 12 + \frac{8}{3} \right] = \pi \left[ 6 + \frac{8}{3} \right] = \pi \left[ \frac{18}{3} + \frac{8}{3} \right] = \pi \left[ \frac{26}{3} \right] \]
07
Final Answer
Multiply through by \(\pi \):\[ V = \frac{26\pi}{3} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Volume of Solids of Revolution
When dealing with a volume of solids of revolution, we're often trying to find the volume of a solid that results when a given region in a plane is rotated about a specific line, known as the "axis of rotation". This means the shape is spun around a line to create a three-dimensional object. This concept is widely used in calculus to help understand and calculate the space a certain shape will occupy when in this new, 3D form.
- The region being rotated is usually bounded by one or more curves or lines.
- The axis of rotation can be either the x-axis, y-axis, or any other line parallel to these axes.
Washer Method
The Washer Method is a technique used to find the volume of a solid of revolution, especially when the solid has a hole in the middle, like a washer. This is a refined way of using the disk method for cases where there's an inner separate boundary creating this hole.
To apply the Washer Method, follow these steps:
To apply the Washer Method, follow these steps:
- Consider a horizontal or vertical slice of the solid to understand the shape of the washer. The outer and inner radii define the thickness of the solid at that slice.
- Calculate the volume of each washer by finding the outer radius and inner radius, which varies with the position along the axis of rotation.
- The formula used is: \[ dV = \pi \left((R_{ ext{outer}})^2 - (R_{ ext{inner}})^2\right) \, dy \] where the integral will sum up these volumes for either the y-axis or the x-axis rotation.
Integral Calculus
Integral Calculus deals with the concept of integration, which is the reverse process of differentiation. It's a core concept in calculus used to find areas, volumes, and central points of more complicated shapes like curves.
Integration allows you to "add up" infinitely small parts to find a "whole". Specifically for volume problems, integration helps calculate the total space occupied by a solid of revolution.
Here’s a simple overview of how integration ties into volume problems:
Integration allows you to "add up" infinitely small parts to find a "whole". Specifically for volume problems, integration helps calculate the total space occupied by a solid of revolution.
Here’s a simple overview of how integration ties into volume problems:
- Determine the function that describes your solid or the region being rotated.
- Use definite integration to sum up all small volume elements (like disks or washers) across an interval.
- The integral \[ \int_{a}^{b} f(y) \, dy \] computes the sum for the bounds \(a\) to \(b\), which in our case corresponds to \(0\) to \(2\) for the integral of the washer method.