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Find the limit of each of the following sequences, using L'H么pital's rule when appropriate. $$ \frac{\sqrt{n}}{\sqrt{n+1}} $$

Short Answer

Expert verified
The limit of the sequence is 1.

Step by step solution

01

Identify the Form

The given sequence is \( \frac{\sqrt{n}}{\sqrt{n+1}} \). Observe that as \( n \to \infty \), both the numerator and the denominator approach infinity. Therefore, this is an \( \frac{\infty}{\infty} \) form and L'H么pital's rule might be applied.
02

Apply L'H么pital's Rule

To apply L'H么pital's Rule, differentiate the numerator and the denominator with respect to \( n \). The derivative of \( \sqrt{n} \) is \( \frac{1}{2\sqrt{n}} \) and the derivative of \( \sqrt{n+1} \) is \( \frac{1}{2\sqrt{n+1}} \). Now, by L'H么pital's Rule, the limit is:\[\lim_{n \to \infty} \frac{\frac{1}{2\sqrt{n}}}{\frac{1}{2\sqrt{n+1}}} = \lim_{n \to \infty} \frac{\sqrt{n+1}}{\sqrt{n}}\]
03

Simplify the Expression

The expression \( \frac{\sqrt{n+1}}{\sqrt{n}} \) can be rewritten as \( \sqrt{\frac{n+1}{n}} \). Simplifying \( \frac{n+1}{n} = 1 + \frac{1}{n} \). So, we have:\[\lim_{n \to \infty} \sqrt{1 + \frac{1}{n}}\]
04

Evaluate the Limit

Evaluate the limit as \( n \to \infty \). As \( n \to \infty \), \( \frac{1}{n} \to 0 \). Therefore, \( \sqrt{1 + \frac{1}{n}} \to \sqrt{1} = 1 \). Thus:\[\lim_{n \to \infty} \frac{\sqrt{n}}{\sqrt{n+1}} = 1\]
05

Conclusion

We have found that the limit of the sequence \( \frac{\sqrt{n}}{\sqrt{n+1}} \) as \( n \to \infty \) is 1. Therefore, the sequence converges to 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequence Limits
When dealing with sequences in calculus, one central task is finding the limit as the sequence progresses towards infinity. A sequence limits helps us understand the behavior of a sequence as the index grows larger and larger. To determine the limit, you observe the pattern of the sequence and identify what value the sequence is approaching. This involves: - Checking the terms of the sequence as they go towards a higher value.- Using algebraic manipulation to simplify the expression.In our exercise, we're interested in \[\lim_{n \to \infty} \frac{\sqrt{n}}{\sqrt{n+1}}\]As the sequence progresses, both the numerator and the denominator grow, which initially suggests an undefined form of infinity over infinity. Solving such limits requires specialized methods such as L'H么pital's Rule or algebraic simplification.
Infinity Forms
Infinity forms, particularly in L'H么pital's Rule, occur when both the numerator and denominator of a fraction tend to infinity. This happens frequently when evaluating limits at infinity.The expression \(\frac{\infty}{\infty}\) doesn't yield useful information about the sequence, thus necessitating the use of powerful mathematical tools like L'H么pital's Rule to resolve it. - Identify expressions that tend toward \(\infty\), \(-\infty\), or indeterminate forms.- Use algebraic manipulation or L'H么pital's Rule to find a solvable form.In this context, once you have identified you're dealing with an \(\frac{\infty}{\infty}\) form, you can differentiate the numerator and denominator to simplify the problem using L'H么pital's Rule.
Derivatives
Derivatives are foundational to applying L'H么pital's Rule when dealing with infinity forms. They allow us to measure how the function changes at any point.Understanding how to compute derivatives helps to manage infinite limits by transforming them into more manageable forms: - Use standard differentiation techniques to differentiate the numerator and denominator.- This often involves simplifying complex polynomials or root expressions.In our specific problem, the derivatives we need are:- Derivative of \(\sqrt{n}\), which is \(\frac{1}{2\sqrt{n}}\).- Derivative of \(\sqrt{n+1}\), which is \(\frac{1}{2\sqrt{n+1}}\).Using these derivatives, L'H么pital's Rule simplifies the original infinity form into a sequence that converges to a limit value.

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