Chapter 6: Problem 415
For the following exercises, find the antiderivatives for the functions. $$\int \frac{x d x}{\sqrt{x^{2}+1}}$$
Short Answer
Expert verified
The antiderivative is \( 2\sqrt{x^2 + 1} + C \).
Step by step solution
01
Use Substitution Method
The integral \( \int \frac{x \, dx}{\sqrt{x^2 + 1}} \) suggests using a substitution to simplify. Let's set \( u = x^2 + 1 \). Then, the derivative of \( u \) with respect to \( x \) is \( \frac{du}{dx} = 2x \), or \( du = 2x \, dx \). To relate it to \( x \, dx \), rewrite as \( x \, dx = \frac{1}{2} du \). Substitute \( u \) and \( x \, dx \) into the integral, resulting in \( \int \frac{1}{\sqrt{u}} \cdot \frac{1}{2} du \), allowing us to take out constants.
02
Simplify the Integral
After substitution, the integral becomes \( \frac{1}{2} \int u^{-\frac{1}{2}} du \). This is a basic power rule integral.
03
Apply the Power Rule for Integration
The power rule for integration states that \( \int u^n du = \frac{u^{n+1}}{n+1} + C \), where \( n eq -1 \). Here \( n = -\frac{1}{2} \). Thus, \( \int u^{-\frac{1}{2}} du = \frac{u^{\frac{1}{2}}}{\frac{1}{2}} + C = 2u^{\frac{1}{2}} + C \).
04
Substitute Back for Original Variable
Substitute back \( u = x^2 + 1 \) into the integral to revert to the variable \( x \). Thus, \( 2u^{\frac{1}{2}} + C \) becomes \( 2(x^2+1)^{\frac{1}{2}} + C \).
05
Simplified Final Answer
So, the antiderivative \( \int \frac{x \, dx}{\sqrt{x^2 + 1}} = 2\sqrt{x^2+1} + C \), where \( C \) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful technique to simplify integral expressions, especially when the direct antiderivative is not readily apparent. In essence, it involves changing variables to transform a complex integral into a simpler form. Here's how it works: when given an integral like \( \int \frac{x \, dx}{\sqrt{x^2 + 1}} \), we look for a substitution that would streamline the process. A good substitution is often a function within the integrand, where its derivative is also present in the expression.
- Consider \( u = x^2 + 1 \). This choice is strategic since its derivative, \( du = 2x \, dx \), closely matches parts of our integral.
- The substitution rewrites the differential as \( x \, dx = \frac{1}{2} du \). This simplifies the integral to \( \int \frac{1}{\sqrt{u}} \cdot \frac{1}{2} du \), making it manageable to solve.
Power Rule for Integration
The power rule for integration is a foundational tool in calculus, letting you find antiderivatives of functions with ease. When applying the power rule, the form should generally be an algebraic expression like \( \int x^n \, dx \). The rule states that if \( n eq -1 \), then \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), where \( C \) is the constant of integration. This rule straightforwardly converts the integral of a power of \( x \) into a solvable expression.
- In the original problem, after substitution, our integral becomes \( \frac{1}{2} \int u^{-\frac{1}{2}} du \).
- Set \( n = -\frac{1}{2} \) in the rule, yielding \( \int u^{-\frac{1}{2}} du = \frac{u^{\frac{1}{2}}}{\frac{1}{2}} + C \).
Constant of Integration
The constant of integration, often denoted as \( C \), is a fundamental component in indefinite integrals. This constant accounts for any constant term that could be part of the original function's antiderivative. Since differentiation of a constant is zero, antiderivatives are unique up to a constant.
- When you find an antiderivative like \( \int \frac{x \, dx}{\sqrt{x^2 + 1}} = 2\sqrt{x^2 + 1} + C \), typical practice involves adding \( C \) to your solution.
- This ensures that all potential functions differing by a constant are represented.