Chapter 5: Problem 418
In the following exercises, use a calculator to graph the antiderivative \(\int f\) with \(C=0\) over the given interval \([a, b]\) . Approximate a value of \(C,\) if possible, such that adding \(C\) to the antiderivative gives the same value as the definite integral \(F(x)=\int_{a}^{x} f(t) d t\). $$[\mathbf{T}] \int \frac{1}{(2 x+2) \sqrt{x}} d x \text { over }[0,6]$$
Short Answer
Step by step solution
Break Down the Integral
Simplify the Function
Integrate Using Substitution
Evaluate Definite Integral
Determine the Appropriate Constant C
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integral
- It requires the function \( f(x) \) to be properly behaved within the interval \([a, b]\).
- The result is a numerical value, representing the accumulated effect of the function across the interval.
- This approach is crucial when evaluating physical quantities like displacement when given a velocity-time graph.
Substitution Method
- Choose a substitution that simplifies the integral, by substituting \( u = g(x) \) such that \( du = g'(x)dx \).
- Rewrite the differential \( dx \) in terms of the new variable \( du \).
- Transform the integral into \( \int f(u) \, du \) and solve.
- By substituting \( u = \sqrt{x} \), we ease computation as \( dx = 2u \, du \) transforms the integral to a recognizable format.
- This results in \( \int \frac{1}{u^2 + 1} \, du \), which is much more straightforward to integrate.
Interval Evaluation
- Compute the antiderivative \( F(x) \) of the integrand \( f(x) \).
- Substitute the upper bound into the antiderivative to get \( F(b) \) and the lower bound to get \( F(a) \).
- The definite integral is then \( F(b) - F(a) \).
- Calculating at the bounds yields \( \arctan(\sqrt{6}) - \arctan(\sqrt{0}) = \arctan(\sqrt{6}) \).
- Such evaluations are helpful for deriving numerical results that relate to real-world problems, like the area under a function representing velocity or other rates of change.
Constant of Integration
- The constant \( C \) ensures all potential antiderivatives are represented, as each could differ by a constant factor.
- For definite integrals, \( C \) is not necessary when evaluating limits, as it cancels itself out when calculating \( F(b) - F(a) \).
- In practice, finding the right constant may require additional conditions from context-specific scenarios to determine precisely or ensure continuity of a solution.