Chapter 5: Problem 291
In the following exercises, use a calculator to estimate the area under the curve using left Riemann sums with 50 terms, then use substitution to solve for the exact answer. $$ y=\frac{x}{\left(x^{2}+1\right)^{2}} \text { over }[-1,1] $$
Short Answer
Expert verified
The left Riemann sum approximates some value, but the exact integral is 0 since it's over a zero-width interval.
Step by step solution
01
Set Up the Left Riemann Sum
To estimate the area using a left Riemann sum, first divide the interval \([-1, 1]\) into 50 equal parts. The width of each subinterval (\(\Delta x\)) is calculated as follows:\[\Delta x = \frac{b-a}{n} = \frac{1 - (-1)}{50} = \frac{2}{50} = 0.04.\]The left endpoints of each subinterval are at \(x_i = -1 + i\Delta x\) where \(i = 0, 1, 2, ..., 49\).
02
Calculate Left Riemann Sum Value
The left Riemann sum is given by:\[L = \sum_{i=0}^{49} f(x_i) \Delta x,\]where \(f(x) = \frac{x}{(x^2 +1)^2}\). Calculate \(f(x_i)\) for each \(i\), multiply by \(\Delta x = 0.04\), and sum the results. This requires plugging each \(x_i\) into the function and adding the products.
03
Set Up the Integral for Exact Area
To find the exact area, we integrate the function over the interval [-1,1]:\[\int_{-1}^{1} \frac{x}{(x^2 + 1)^2} \, dx.\]Recognize this as a standard substitution problem for integration.
04
Use Substitution Method
Choose \(u = x^2 + 1\), then \(du = 2x \, dx\), or \(x \, dx = \frac{du}{2}\).Adjust the limits for \(u\):- When \(x = -1\), \(u = (-1)^2 + 1 = 2\).- When \(x = 1\), \(u = 1^2 + 1 = 2\).So, the limits remain the same (\([2,2]\)), indicating the integral evaluates as zero due to the limits being equal.
05
Evaluate the Integral
Rewriting the integral with substitution gives:\[\int_{2}^{2} \frac{1}{u^2} \cdot \frac{du}{2}.\]Since we integrate over an interval with equal limits, the integral evaluates to zero. Regardless of the function, the area under the curve is zero.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful technique used in integral calculus to simplify the integration process. It involves changing variables to make an integral easier to solve. Here's the basic idea: you replace a complicated part of an integrand with a single variable "u". This often turns a complex integral into a simpler one.
In the given exercise, we use substitution to evaluate the integral \(\int_{-1}^{1} \frac{x}{(x^2 + 1)^2} \, dx\). We set \(u = x^2 + 1\), which simplifies the expression considerably. Then, differentiate to find \(du = 2x \, dx\), or \(x \, dx = \frac{du}{2}\).
In the given exercise, we use substitution to evaluate the integral \(\int_{-1}^{1} \frac{x}{(x^2 + 1)^2} \, dx\). We set \(u = x^2 + 1\), which simplifies the expression considerably. Then, differentiate to find \(du = 2x \, dx\), or \(x \, dx = \frac{du}{2}\).
- Choose \(u\) to simplify the integrand.
- Express \(dx\) in terms of \(du\).
- Change the limits of integration according to the substitution.
- Substitute \(u\) and integrate.
Integral Calculus
Integral calculus is a fundamental concept in mathematics that focuses on the accumulation of quantities, such as areas under a curve. It is broadly divided into two main operations: the indefinite integral, which is an antiderivative, and the definite integral, which calculates a specific quantity, such as an area.
In the exercise, our task is to find the area under the curve \(y = \frac{x}{(x^2 +1)^2}\) over the interval \([-1,1]\) using the definite integral. This involves calculating \(\int_{-1}^{1} \frac{x}{(x^2 + 1)^2} \, dx\). Such processes are essential for understanding the nature of curves and surfaces.
In the exercise, our task is to find the area under the curve \(y = \frac{x}{(x^2 +1)^2}\) over the interval \([-1,1]\) using the definite integral. This involves calculating \(\int_{-1}^{1} \frac{x}{(x^2 + 1)^2} \, dx\). Such processes are essential for understanding the nature of curves and surfaces.
- Indefinite integrals provide general solutions for antiderivatives.
- Definite integrals compute exact quantities over specific intervals.
- Solving integrals often requires techniques like substitution and integration by parts.
Area Under the Curve
The concept of finding the area under a curve is crucial in many fields, such as physics, engineering, and economics. It provides insights into total quantities, like mass or cost, accumulated over a range of values.
In this context, the area under the curve of \(y = \frac{x}{(x^2 + 1)^2}\) from \(-1\) to \(1\) is what we aim to calculate. Using integral calculus, this figure is expressed as a definite integral. When approached with substitution, as done in the exercise, it simplifies the complexity of the function under consideration.
In this context, the area under the curve of \(y = \frac{x}{(x^2 + 1)^2}\) from \(-1\) to \(1\) is what we aim to calculate. Using integral calculus, this figure is expressed as a definite integral. When approached with substitution, as done in the exercise, it simplifies the complexity of the function under consideration.
- The area is determined by computing a definite integral of the function.
- Riemann sums provide an estimation method through partitioned intervals.
- Definite integrals offer exact solutions for the calculated area.