Chapter 5: Problem 269
In the following exercises, find the antiderivative using the indicated substitution. $$ \int \cos ^{3} \theta d \theta ; u=\sin \theta\left(\operatorname{Hint} \cos ^{2} \theta=1-\sin ^{2} \theta\right) $$
Short Answer
Expert verified
The antiderivative is \( \sin \theta - \frac{(\sin \theta)^3}{3} + C \).
Step by step solution
01
Substitute the Trigonometric Identity
First, use the hint provided in the problem to express \( \cos^2 \theta \) in terms of \( \sin \theta \). We have \( \cos^2 \theta = 1 - \sin^2 \theta \). Therefore, \( \cos^3 \theta = \cos \theta \cdot \cos^2 \theta = \cos \theta (1 - \sin^2 \theta) \).
02
Express in Terms of u
Since \( u = \sin \theta \), we express the integral in terms of \( u \). Therefore, \( \cos \theta = \sqrt{1-u^2} \), but note that with the substitution \( du = \cos \theta \, d\theta \), we can directly replace \( \cos \theta \, d\theta = du \). The expression becomes \[ \int \cos^3 \theta \, d\theta = \int \cos \theta (1 - \sin^2 \theta) \, d\theta = \int \cos \theta (1 - u^2) \, d\theta. \] But, recognizing \( \cos \theta \, d\theta = du\), the integral becomes \[ \int (1-u^2) \, du. \]
03
Integrate with Respect to u
Now that we have the integral in terms of \( u \), integrate with respect to \( u \): \[ \int (1 - u^2) \, du = \int 1 \, du - \int u^2 \, du. \] This yields \[ u - \frac{u^3}{3} + C, \] where \( C \) is the constant of integration.
04
Substitute Back to Original Variable
Finally, substitute back \( u = \sin \theta \) into the antiderivative: \[ u - \frac{u^3}{3} + C = \sin \theta - \frac{(\sin \theta)^3}{3} + C. \] This gives the antiderivative in terms of \( \theta \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Substitution
Trigonometric substitution is a clever technique used in calculus to simplify integrals involving trigonometric functions. In our exercise, we're dealing with an integral that involves powers of cosine. The hint suggests using a trigonometric identity to transform part of the expression. This identity helps us rewrite
- \( \cos^2 \theta = 1 - \sin^2 \theta \)
- \( \cos^3 \theta = \cos \theta (1 - \sin^2 \theta) \)
Integration Techniques
Integration techniques include various methods used to solve integrals that can't be immediately evaluated. In the given problem, we've used a combination of substitutions and algebraic manipulation to simplify the process.
Here's how it works:
Integration techniques like substitution are invaluable because they turn complex-looking integrals into simpler tasks. They often produce expressions that are algebraically manageable, allowing us to neatly find the antiderivatives.
Here's how it works:
- First, we use trigonometric identities to rewrite the integral in a simpler form.
- We then perform a substitution so that the integral can be expressed in terms of a single variable \( u \), easing the computation.
Integration techniques like substitution are invaluable because they turn complex-looking integrals into simpler tasks. They often produce expressions that are algebraically manageable, allowing us to neatly find the antiderivatives.
Calculus Exercises
Calculus exercises often involve multiple steps and require a strong understanding of core calculus concepts, like integration and substitution. This exercise demonstrates the thought process behind solving integrals by using substitutions. It's a classic example of how calculus problems require a combination of algebraic manipulation and strategic thinking.
Here’s a brief breakdown:
Here’s a brief breakdown:
- Identify the trigonometric identities and their potential to simplify the integral.
- Use substitution to transform the integral into an easier form to compute.
- Perform the integration and back-substitute to the original variable.