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In the following exercises, verify each identity using differentiation. Then, using the indicated \(u\) -substitution, identify \(f\) such that the integral takes the form \(\int f(u) d u .\) $$ \int \frac{x^{2}}{\sqrt{x-1}} d x(x>1)=\frac{2}{15} \sqrt{x-1}\left(3 x^{2}+4 x+8\right)+C ; u=x-1 $$

Short Answer

Expert verified
Differentiate the right side using the product rule; verify it matches integrand, then use substitution to find \(f(u) = u^{1/2} + 2u^{-1/2} + u^{-3/2}\).

Step by step solution

01

Differentiate the Right Side

To verify the given integral identity, we start by differentiating the right side of the equation. The expression is \[ \frac{2}{15} \sqrt{x-1}(3x^{2} + 4x + 8) + C. \] The derivative of a constant \( C \) is zero. So, we need to use the product rule to differentiate \( \sqrt{x-1}(3x^{2} + 4x + 8) \). Let \( u = \sqrt{x-1} \) and \( v = 3x^{2} + 4x + 8 \), then take the derivative using \( (uv)' = u'v + uv' \).
02

Compute Derivative u' and v'

The derivative of \( u = \sqrt{x-1} \) is \( u' = \frac{1}{2\sqrt{x-1}} \). The derivative of \( v = 3x^{2} + 4x + 8 \) is \( v' = 6x + 4 \).
03

Apply Product Rule

Using the product rule \((uv)' = u'v + uv'\), substitute for \(u, v, u',\) and \(v'\).\[ (\sqrt{x-1})'(3x^2 + 4x + 8) + \sqrt{x-1}(6x + 4). \] This simplifies to \[ \frac{1}{2\sqrt{x-1}}(3x^2 + 4x + 8) + \sqrt{x-1}(6x + 4). \] Multiply all terms by \(\frac{2}{15}\) as part of the differentiation.
04

Simplify the Derivative

Simplify the expression obtained from the product rule. The first term becomes \( \frac{(3x^2 + 4x + 8)}{15\sqrt{x-1}} \), and the second term becomes \( \frac{2}{15} \times (6x + 4)\sqrt{x-1}. \) Simplify both expressions and add them together.
05

Confirm the Result Matches the Integrand

After simplifying, the resulting expression should match the original integrand \( \frac{x^{2}}{\sqrt{x-1}}\). If the derivative calculations are correct, this confirms the identity.
06

Identify Substitution for Integral Change

Use the substitution \( u = x - 1 \), then \( du = dx \). In terms of \( u \), the integral becomes \[ \int \frac{(u+1)^2}{\sqrt{u}} \, du. \] The next goal is to identify \( f(u) \) that corresponds to this expression.
07

Rewrite and Simplify the Integral

Expand \( (u+1)^2 \) to become \( u^2 + 2u + 1 \), and rewrite the integral as \[ \int \left(u^{1/2} + 2u^{-1/2} + u^{-3/2}\right) \, du. \] Thus, \( f(u) = u^{1/2} + 2u^{-1/2} + u^{-3/2}. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a mathematical process that computes the rate at which a function is changing at any given point. It is one of the key concepts in calculus. Differentiation allows us to find derivatives, which tell us how a function's value changes in response to changes in input. In the context of our exercise, differentiation is used to verify the given integral identity. We do this by differentiating the right side of the expression to see if it matches the integrand on the left side. This involves applying rules such as the product rule, which we'll discuss next. Differentiation is fundamental because it connects various areas of calculus, facilitating integration and understanding of functions' behavior.
Product Rule
The product rule is a specific rule of differentiation used when a function is the product of two other functions. It states that the derivative of the product of two functions, say, \( u(x) \) and \( v(x) \), is given by:\[ (uv)' = u'v + uv' \]This rule is essential because it enables us to handle situations where functions are multiplied, such as in the expression \( \sqrt{x-1}(3x^2 + 4x + 8) \). In our exercise, the product rule is employed to differentiate this expression—as the product of \( u = \sqrt{x-1} \) and \( v = 3x^2 + 4x + 8 \). Calculating the derivatives of \( u \) and \( v \) and substituting them into the product rule formula allows us to examine how the overall function changes, helping us verify the integral's validity.
Integral Identity
An integral identity is an equation that demonstrates the equality of two expressions by integrating both sides. The principle here is that when differentiated, both sides of the equation should yield the same function, confirming the identity.In this exercise, our goal is to prove the identity:\[ \int \frac{x^2}{\sqrt{x-1}} \, dx = \frac{2}{15} \sqrt{x-1}(3x^2 + 4x + 8) + C \]To verify this, we differentiate the right side and compare it to the integrand \( \frac{x^2}{\sqrt{x-1}} \) on the left side. If both are identical, the integral identity is validated. Integral identities are crucial as they enable functional transformations and simplifications, particularly in calculus, where identifying similar expressions helps in evaluating integrals and finding solutions.
Substitution Method
The substitution method is a popular technique used to simplify integration problems by making a suitable substitution that transforms the integral into a more manageable form. It often involves substituting expressions with a new variable to rewrite the integral.In our case, we use the substitution \( u = x-1 \). This choice changes the variable from \( x \) to \( u \), making the integral easier to solve by converting it into:\[ \int \frac{(u+1)^2}{\sqrt{u}} \, du \]The main goal is to identify a simpler function \( f(u) \) that the new integral represents. By expanding and simplifying \( (u+1)^2 \), we rewrite the original complex integrand in terms of powers of \( u \), ultimately giving us \( f(u) = u^{1/2} + 2u^{-1/2} + u^{-3/2} \). This method streamlines the process of integration, turning difficult problems into basic ones.

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