Chapter 5: Problem 213
Write an integral that expresses the increase in the perimeter \(P(s)\) of a square when its side length \(s\) increases from 2 units to 4 units and evaluate the integral.
Short Answer
Expert verified
The increase in the perimeter is 8 units.
Step by step solution
01
Understand the Problem
To find the increase in the perimeter of a square as its side length changes from 2 to 4 units, we need to express the perimeter as a function of the side length and identify the integral that represents this change.
02
Define the Perimeter Function
The perimeter \( P(s) \) of a square with side length \( s \) is defined by the equation \( P(s) = 4s \), because a square has four equal sides.
03
Set Up the Integral Expression
To find the increase in the perimeter as \( s \) increases from 2 to 4, we set up the integral \[ \int_{2}^{4} P'(s) \, ds \] where \( P'(s) = \frac{d}{ds}(4s) = 4 \) represents the constant rate of change of the perimeter with respect to \( s \).
04
Evaluate the Integral
Evaluate \[ \int_{2}^{4} 4 \, ds \]. This simplifies to \[ 4[s]_{2}^{4} = 4(4 - 2) = 4 \times 2 = 8 \].
05
Interpret the Result
The evaluation of the integral gives us the increase in the perimeter, which is 8 units. This means that as the side length of the square increases from 2 units to 4 units, the perimeter increases by 8 units.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Perimeter of a Square
A square is a simple geometric shape, and its perimeter is the total distance around its edges. Calculating the perimeter is straightforward because a square has four equal sides. The formula for the perimeter of a square is:
- \( P(s) = 4s \)
Rate of Change
In mathematics, the rate of change refers to how a quantity changes over a specific interval. For a square, if the side length changes, the perimeter changes at a predictable rate. Specifically, when you differentiate the perimeter \( P(s) = 4s \) with respect to \( s \), you find that the rate of change of the perimeter is a constant.
- \( P'(s) = \frac{d}{ds}(4s) = 4 \)
Evaluating Integrals
Evaluating integrals is a fundamental tool in calculus used to calculate accumulated quantities, such as area under a curve or the total change between two points. An integral, like \( \int_{a}^{b} f(x) \, dx \), represents the sum of infinitesimal changes from \( a \) to \( b \). In our example with the square's perimeter, the integral \( \int_{2}^{4} 4 \, ds \) computes the total increase in the perimeter as the side length increases from 2 to 4.
The function \( 4 \) is constant, simplifying the integral to:
The function \( 4 \) is constant, simplifying the integral to:
- \( 4[s]_{2}^{4} = 4(4 - 2) = 8 \)