Chapter 4: Problem 51
Find the linear approximation \(L(x)\) to \(y=f(x)\) near \(x=a\) for the function. \(f(x)=\frac{1}{x}, a=2\)
Short Answer
Expert verified
The linear approximation is \( L(x) = 1 - \frac{1}{4}x \).
Step by step solution
01
Understand the Problem
To find the linear approximation, or the linearization of a function near a specified point, we need to identify the function and the point around which we are approximating. Here, the function is \( f(x) = \frac{1}{x} \) and we are approximating around \(x = a = 2\).
02
Calculate the Derivative
The formula for the linear approximation is \( L(x) = f(a) + f'(a)(x-a) \). First, we need to find the derivative \( f'(x) \). For \( f(x) = \frac{1}{x} \), the derivative is \( f'(x) = -\frac{1}{x^2} \).
03
Evaluate the Function and its Derivative at x = a
Calculate \( f(a) \) and \( f'(a) \) at \(x = 2\). We have:\[ f(2) = \frac{1}{2} \]\[ f'(2) = -\frac{1}{2^2} = -\frac{1}{4} \]
04
Apply the Linear Approximation Formula
Substitute \( f(a) \), \( f'(a) \), and \( a = 2 \) into the linear approximation formula:\[ L(x) = f(2) + f'(2)(x - 2) = \frac{1}{2} - \frac{1}{4}(x - 2) \]
05
Simplify the Expression
Simplify the linear approximation expression:\[ L(x) = \frac{1}{2} - \frac{1}{4}x + \frac{1}{2} \]Combine like terms:\[ L(x) = 1 - \frac{1}{4}x \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Derivatives
To understand linear approximation, it's important to grasp the concept of derivatives. A derivative represents the rate of change of a function with respect to a variable. It's like measuring how steep a hill is at any point. By calculating a derivative, you find how much the function's output (y-value) changes as the input (x-value) changes by a small amount.
In practical terms:
Understanding this tool helps create an accurate linear approximation that mimics the original function closely at the point of interest.
In practical terms:
- When you compute the derivative of a function, it tells you how the function behaves locally.
- It gives you the slope of the tangent line to the graph of the function at a specific point.
Understanding this tool helps create an accurate linear approximation that mimics the original function closely at the point of interest.
The Role of the Tangent Line
A tangent line is a straight line that touches a curve at a single point without crossing it. It describes the instantaneous direction of the curve at that point. In the context of linear approximation, the tangent line at a point provides the simplest linear model for the behavior of the function near that point.
For a curve shaped by \( f(x) = \frac{1}{x} \), when we compute its tangent at \( x = 2 \), the slope of the tangent line is given by the derivative \( f'(2) = -\frac{1}{4} \). This slope shows how steeply the function rises or falls at that point.
For a curve shaped by \( f(x) = \frac{1}{x} \), when we compute its tangent at \( x = 2 \), the slope of the tangent line is given by the derivative \( f'(2) = -\frac{1}{4} \). This slope shows how steeply the function rises or falls at that point.
- The tangent line plays a crucial role in linear approximation because it allows us to simplify complex curves into straight lines which are easier to work with mathematically.
- It's used together with the function value at that point, \( f(2) = \frac{1}{2} \), to form the linear approximation.
Function Approximation
Function approximation uses simple functions to represent more complicated ones over a specific range. In our case, linear approximation is utilized, which involves approximating a nonlinear function with a linear one near a specific point. It simplifies complex calculations and is particularly useful when models need to be computed quickly.
- Linear approximations are often expressed in the form \( L(x) = f(a) + f'(a)(x-a) \), where \( f(a) \) is the function value at a known point and \( f'(a) \) is the slope of the function at that same point.
- For our function \( f(x) = \frac{1}{x} \), the linear approximation around \( x = 2 \) results in \( L(x) = 1 - \frac{1}{4}x \).
Applications in Calculus
Linear approximation is one of many calculus applications that solve real-world problems by simplifying complex mathematical models. Calculus tools help in predicting changes, optimizing functions, and modeling dynamic systems.
- In engineering, linear approximation assists in designing systems where precise models of component behavior are complicated or computationally expensive.
- Scientists sometimes apply linear approximations to model physical phenomena, such as small oscillations around equilibrium points.
- In economics, linear models can simplify consumer behavior modeling, making problematic computations manageable.