Chapter 4: Problem 478
For the following exercises, find the antiderivative \(F(x)\) of each function \(f(x)\). $$f(x)=x^{1 / 3}+(2 x)^{1 / 3}$$
Short Answer
Expert verified
The antiderivative is \( F(x) = \frac{3}{4}x^{4/3} + 2^{1/3} \cdot \frac{3}{4}x^{4/3} + C \).
Step by step solution
01
Break down the function
The function given is \( f(x) = x^{1/3} + (2x)^{1/3} \). Separate it into two parts, \( x^{1/3} \) and \( (2x)^{1/3} \), for individual integration.
02
Integrate the first term
To find the antiderivative of the first term \( x^{1/3} \), use the formula for the antiderivative of \( x^n \), which is \( \frac{x^{n+1}}{n+1} \) (for \( n eq -1 \)). Here, \( n = 1/3 \), so the antiderivative is \( \frac{x^{1/3 + 1}}{1/3 + 1} = \frac{x^{4/3}}{4/3} = \frac{3}{4}x^{4/3} \).
03
Integrate the second term
Rewrite the second term \( (2x)^{1/3} \) as \( 2^{1/3} \cdot x^{1/3} \). Using the constant multiple rule, factor out the constant \( 2^{1/3} \) from the integral. Thus, the integral becomes: \( 2^{1/3} \cdot \int x^{1/3} \, dx \). From Step 2, we know the integral of \( x^{1/3} \) is \( \frac{3}{4}x^{4/3} \), so this becomes \( 2^{1/3} \cdot \frac{3}{4}x^{4/3} \).
04
Combine the results
Combine the antiderivatives from Step 2 and Step 3 to find \( F(x) \). The antiderivative of \( f(x) \) is: \[ F(x) = \frac{3}{4}x^{4/3} + 2^{1/3} \cdot \frac{3}{4}x^{4/3} + C \], where \( C \) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration techniques
Integration is a fundamental concept in calculus, just like its counterpart, differentiation. While differentiation deals with finding the rate of change, integration focuses on the accumulation of quantities. In particular, an antiderivative of a function represents the family of all functions that differentiate into the given function.
You can think of integration as a process of finding the "area under a curve." Let's explore some techniques for solving integrals, which are crucial for finding antiderivatives:
You can think of integration as a process of finding the "area under a curve." Let's explore some techniques for solving integrals, which are crucial for finding antiderivatives:
- **Breaking down complex functions:** When faced with a difficult function, like in our exercise, splitting it into simpler terms can make integration easier.
- **Using known formulas:** It helps to remember and use standard integration formulas, like those involving powers of x, to quickly find antiderivatives.
Power rule for integration
The power rule for integration is a straightforward and practical technique that applies to any function of the form \( x^n \), where \( n eq -1 \). This rule states that the integral of \( x^n \) is \( \frac{x^{n+1}}{n+1} \). It’s a direct generalization of finding antiderivatives of power functions.
In our example, the function \( f(x) = x^{1/3} \) is easily integrated using this rule since the exponent 1/3 is neither -1 nor any negative integer. Following the power rule:
\[ \int x^{1/3} \, dx = \frac{x^{4/3}}{4/3} = \frac{3}{4}x^{4/3} \]
Notice how the denominator \( n+1 \) adjusts the power of the variable, and dividing by \( n+1 \) correctly scales the result. This formula provides an essential building block for more complex integrals and understanding it thoroughly will help tackle a wide variety of integration problems. Always add the constant of integration \( C \) at the end, as integration results in a family of possible functions, differing by a constant.
In our example, the function \( f(x) = x^{1/3} \) is easily integrated using this rule since the exponent 1/3 is neither -1 nor any negative integer. Following the power rule:
\[ \int x^{1/3} \, dx = \frac{x^{4/3}}{4/3} = \frac{3}{4}x^{4/3} \]
Notice how the denominator \( n+1 \) adjusts the power of the variable, and dividing by \( n+1 \) correctly scales the result. This formula provides an essential building block for more complex integrals and understanding it thoroughly will help tackle a wide variety of integration problems. Always add the constant of integration \( C \) at the end, as integration results in a family of possible functions, differing by a constant.
Constant multiple rule
The constant multiple rule is another handy integration property that enables the integration of terms with constant factors. It states that: if \( c \) is a constant, then the integral of \( c \cdot f(x) \) with respect to \( x \) is \( c \cdot \int f(x) \, dx \). This means you can "pull out" constants from an integral and deal with them separately.
For example, consider \( (2x)^{1/3} \) in our exercise. We rewrite it as \( 2^{1/3} \cdot x^{1/3} \) to apply this rule.
In this case, \( 2^{1/3} \) is a constant, so we factor it outside the integral:
\[ 2^{1/3} \cdot \int x^{1/3} \, dx \]
This simplifies the process as now you're only concerned about integrating \( x^{1/3} \) using known techniques like the power rule. Finally, multiply the result by the constant as follows:
\( 2^{1/3} \cdot \frac{3}{4} x^{4/3} \)
Utilizing the constant multiple rule saves time and can simplify complex integrals into manageable pieces, making it a valuable tool in the integration toolkit.
For example, consider \( (2x)^{1/3} \) in our exercise. We rewrite it as \( 2^{1/3} \cdot x^{1/3} \) to apply this rule.
In this case, \( 2^{1/3} \) is a constant, so we factor it outside the integral:
\[ 2^{1/3} \cdot \int x^{1/3} \, dx \]
This simplifies the process as now you're only concerned about integrating \( x^{1/3} \) using known techniques like the power rule. Finally, multiply the result by the constant as follows:
\( 2^{1/3} \cdot \frac{3}{4} x^{4/3} \)
Utilizing the constant multiple rule saves time and can simplify complex integrals into manageable pieces, making it a valuable tool in the integration toolkit.