Chapter 4: Problem 466
Show that \(F(x)\) are antiderivatives of \(f(x)\). \(\quad F(x)=x^{2}+4 x+1, f(x)=2 x+4\)
Short Answer
Expert verified
Yes, \( F(x) \) is an antiderivative of \( f(x) \).
Step by step solution
01
Understanding the Problem
We are given two functions: \( F(x) = x^2 + 4x + 1 \) and \( f(x) = 2x + 4 \). We need to show that \( F(x) \) is an antiderivative of \( f(x) \). This means that the derivative of \( F(x) \) with respect to \( x \) should equal \( f(x) \).
02
Differentiate \( F(x) \)
Compute the derivative of \( F(x) = x^2 + 4x + 1 \). According to the power rule, the derivative of \( x^n \) is \( n \, x^{n-1} \). Thus,\[ \frac{d}{dx}(x^2) = 2x, \quad \frac{d}{dx}(4x) = 4, \quad \text{and} \quad \frac{d}{dx}(1) = 0. \] Therefore, the derivative \( F'(x) \) is:\[ F'(x) = 2x + 4. \]
03
Compare Derivatives
Compare the derivative \( F'(x) = 2x + 4 \) to the function \( f(x) = 2x + 4 \). Since \( F'(x) = f(x) \), \( F(x) \) is indeed an antiderivative of \( f(x) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation
Differentiation is a fundamental concept in calculus that involves finding the derivative of a function. The derivative represents the rate at which a function is changing at any given point. In simpler terms, it tells us how quickly or slowly the value of a function changes when the input of the function is varied.
When you differentiate, you're essentially looking to find how a function behaves locally, in close proximity to a specified point. Differentiation provides insight into the slope of the curve of the function at any given point on its graph.
Here's a simple way to visualize it:
When you differentiate, you're essentially looking to find how a function behaves locally, in close proximity to a specified point. Differentiation provides insight into the slope of the curve of the function at any given point on its graph.
Here's a simple way to visualize it:
- Imagine driving a car along a road that corresponds to the graph of your function.
- The derivative at any point gives the speedometer reading – your speed (rate of change) at that exact moment.
Power Rule
The power rule is a straightforward and powerful tool used in calculus to differentiate functions of the form \( x^n \). This rule states that the derivative of \( x^n \) with respect to \( x \) is \( nx^{n-1} \). This simplifies the differentiation process significantly and allows us to handle a wide variety of polynomial functions with ease.
The power rule can be broken down into these simple steps:
Using the power rule, we can swiftly handle more complex functions such as \( F(x) = x^2 + 4x + 1 \), breaking them down into manageable parts and applying the rule to each term separately.
The power rule can be broken down into these simple steps:
- Identify the exponent \( n \) of the variable \( x \).
- Multiply the entire term by \( n \).
- Reduce the exponent by one, going from \( n \) to \( n-1 \).
Using the power rule, we can swiftly handle more complex functions such as \( F(x) = x^2 + 4x + 1 \), breaking them down into manageable parts and applying the rule to each term separately.
Derivative Computation
Computing the derivative of a function involves applying differentiation rules to find the derivative's form. This process helps in determining how a function's outputs are changing in response to changes in its inputs. Let's break down the steps involved using the example function \( F(x) = x^2 + 4x + 1 \):
For \( F(x) = 4x \), applying the rule gives us \( 4 \).
For constants like \( 1 \), the derivative is always zero since constants do not change.
Collectively, \( F'(x) = 2x + 4 \) results from this computation, and, as demonstrated, this derivative matches the function \( f(x) = 2x + 4 \), proving \( F(x) \) is indeed an antiderivative of \( f(x) \).
- Identify each term in the function.
- Apply the power rule and differentiate each term individually.
- Combine all derivative terms to form \( F'(x) \).
For \( F(x) = 4x \), applying the rule gives us \( 4 \).
For constants like \( 1 \), the derivative is always zero since constants do not change.
Collectively, \( F'(x) = 2x + 4 \) results from this computation, and, as demonstrated, this derivative matches the function \( f(x) = 2x + 4 \), proving \( F(x) \) is indeed an antiderivative of \( f(x) \).