Chapter 4: Problem 401
For the following exercises, use a calculator to graph the function and estimate the value of the limit, then use L'Hôpital's rule to find the limit directly. $$ \lim _{x \rightarrow \pi} \frac{1+\cos x}{\sin x} $$
Short Answer
Expert verified
The limit of the function as \( x \to \pi \) is 0.
Step by step solution
01
Understand the Problem
We need to estimate the limit \( \lim_{x \to \pi} \frac{1+\cos x}{\sin x} \) by graphing the function and then confirm our estimate using L'Hôpital's rule.
02
Estimate Using Graphing
Graph the functions \( y = 1+\cos x \) and \( y = \sin x \) using a calculator. Look at the behavior of the function \( \frac{1+\cos x}{\sin x} \) as \( x \) approaches \( \pi \). Notice that both the numerator and the denominator are equal to 0 at \( x = \pi \), suggesting a point of indeterminacy.
03
Confirm Indeterminate Form
Recognize that as \( x \to \pi \), both \( 1+\cos x \) and \( \sin x \) approach 0, creating a \( \frac{0}{0} \) indeterminate form, which allows us to use L'Hôpital's Rule.
04
Apply L'Hôpital's Rule
Differentiate the numerator: \( \frac{d}{dx}(1+\cos x) = -\sin x \). Differentiate the denominator: \( \frac{d}{dx}(\sin x) = \cos x \). Apply L'Hôpital's Rule to get: \[\lim_{x \to \pi} \frac{1+\cos x}{\sin x} = \lim_{x \to \pi} \frac{-\sin x}{\cos x}\]
05
Evaluate the New Limit
Substitute \( x = \pi \) into \( \frac{-\sin x}{\cos x} \). We obtain:\[\lim_{x \to \pi} \frac{-\sin x}{\cos x} = \frac{-\sin(\pi)}{\cos(\pi)} = \frac{0}{-1} = 0\]Thus, the limit is 0.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
L'Hôpital's rule
L'Hôpital's Rule is a technique used in calculus to find the limit of indeterminate forms like \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \). It offers a way to evaluate limits by differentiating the numerator and the denominator separately.- The rule applies only when the original limit results in an indeterminate form.- By taking the derivative of the numerator and the denominator, you transform the problem into a simpler form.Here's a step-by-step on how to apply it:
- Identify the indeterminate form at a particular point (e.g., at \( x = \pi \) in our problem).
- Take the derivative of the numerator and the denominator.
- Compute the limit again with these derivatives, which often resolves the indeterminacy.
Indeterminate forms
Indeterminate forms are expressions in mathematical limits that do not lead directly to a specific value. They arise when both the numerator and the denominator of a fraction approach zero (\( \frac{0}{0} \)) or infinity (\( \frac{\infty}{\infty} \)). These forms signal ambiguity, because standard arithmetic operations cannot solve them directly.Different types of indeterminate forms include:
- \( \frac{0}{0} \)
- \( \frac{\infty}{\infty} \)
- \( 0 \cdot \infty \)
- \( \infty - \infty \)
- \( 1^\infty \)
- \( 0^0 \)
- \( \infty^0 \)
Graphing functions
Graphing functions helps to visualize the behavior of expressions as variables approach certain values. This is especially helpful in estimating limits. By plotting \( y = 1+\cos x \) and \( y = \sin x \), you can visually identify points where the function approaches an indeterminate form.When approaching a point (like \( x = \pi \)), observing how the graph behaves is essential. In cases where both numerator and denominator blow up to zero, the graph may suggest a point of indeterminacy. You can use graphing to:
- Estimate the value of a limit by checking the function's behavior as it nears a specific point.
- See if the function approaches a certain value or oscillates widely.
- Distinguish between removable discontinuities and true anomalies.