Chapter 4: Problem 218
For the following exercises, draw a graph that satisfies the given specifications for the domain \(x=[-3,3] .\) The function does not have to be continuous or differentiable. $$ f^{\prime \prime}(x) < 0 $$ $$ -1 < x < 1, f^{\prime \prime}(x) > 0,-3 < x < -1,1 < x < 3 $$ local maximum at \(x=0,\) local minima at \(x=\pm 2\)
Short Answer
Step by step solution
Understanding the Second Derivative Conditions
Local Maximum and Minimum Analysis
Sketching the Graph Based on Given Conditions
Final Graph Review and Adjustments
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Concavity
Conversely, when a function is concave down, it looks like a frown. This indicates that the slope of the curve is decreasing. For such a shape, \( f''(x) \) is less than zero. Here the curve opens downwards, akin to an upside-down bowl. Understanding these concavity conditions is crucial in anticipating the general shape of a graph, especially when dealing with intervals, like \(-1 < x < 1\) being concave down, or \(-3 < x < -1\) and \(1 < x < 3\) being concave up.
These clues provide insights into how to sketch a graph even before knowing detailed data points.
Identifying Local Maximum
At this peak, the derivative changes sign — it moves from positive on one side, to negative on the other side, signifying a top point on a mountain. In this exercise, it's specified that there's a local maximum at \( x=0 \). This implies that at this point, the graph has a peak, standing taller than the nearby points.
- The slope here goes from increasing to decreasing.
- The graph meets a crest at \( x=0 \) due to \( f'(x) \) moving from positive to negative.
Understanding Local Minimum
In the given exercise, the graph specifies local minima at \( x = \pm 2 \). These points mean the graph dips lower than the nearby positions, forming a bottom amid surrounding points. Understanding this helps predict how the graph should fall into these local valleys:
- At these points, the curve bottoms out.
- The slope transitions from sloping down to sloping up.
Role of the Second Derivative
For instance:
- If \( f''(x) > 0 \), it signals that the curve is concave up in that interval.
- Conversely, if \( f''(x) < 0 \), it signals a concave down shape.
By utilizing these values, we smoothly transition through every portion of the graph, aligning each section’s gradient and shape correctly.