Chapter 3: Problem 57
Use the definition of a derivative to find \(f^{\prime}(x)\). $$ f(x)=4 x^{2} $$
Short Answer
Expert verified
The derivative \( f'(x) = 8x \).
Step by step solution
01
Recall the Definition of a Derivative
The derivative of a function \(f(x)\), denoted by \(f'(x)\), is defined by the limit: \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \] This definition will be used to find the derivative of \(f(x) = 4x^2\).
02
Substitute Function into the Derivative Definition
Substitute \(f(x) = 4x^2\) into the derivative formula:\[ f'(x) = \lim_{h \to 0} \frac{4(x+h)^2 - 4x^2}{h} \]
03
Expand the Expression
Expand \((x+h)^2\): \[ (x+h)^2 = x^2 + 2xh + h^2 \] Substitute this back into the limit expression:\[ f'(x) = \lim_{h \to 0} \frac{4(x^2 + 2xh + h^2) - 4x^2}{h} \]
04
Simplify the Expression
Distribute the 4 and simplify:\[ f'(x) = \lim_{h \to 0} \frac{4x^2 + 8xh + 4h^2 - 4x^2}{h} \] Cancel \(4x^2\):\[ f'(x) = \lim_{h \to 0} \frac{8xh + 4h^2}{h} \]
05
Factor and Compute the Limit
Factor \(h\) out from the numerator:\[ f'(x) = \lim_{h \to 0} \frac{h(8x + 4h)}{h} \] Cancel \(h\):\[ f'(x) = \lim_{h \to 0} (8x + 4h) \] Now, as \(h\) approaches 0, the expression becomes:\[ f'(x) = 8x \]
06
Conclusion
Thus, the derivative of the function \(f(x) = 4x^2\) is \( f'(x) = 8x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
limit definition of derivative
Understanding the limit definition of a derivative is crucial in calculus. It allows us to determine the rate at which a function's value changes with respect to changes in its input value. The formal definition is given as the limit process: \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \] Here, \(h\) is an infinitesimally small number that represents a tiny change in \(x\). The expression \(f(x+h) - f(x)\) gives the change in the function's output. The entire fraction represents the average rate of change over a small interval, and taking the limit as \(h\) approaches zero gives the instantaneous rate of change, which is the derivative.
- The numerator \(f(x+h) - f(x)\) captures the change in function value.
- Dividing by \(h\) scales this change per unit change in \(x\).
- The limit \(h \to 0\) refines this to an "instantaneous" change.
polynomial functions
Polynomial functions, like \(f(x) = 4x^2\), are algebraic expressions consisting of terms in the form \(ax^n\), where \(a\) is a coefficient, and \(n\) is a non-negative integer known as the degree of the term. They have several properties and features that make them one of the fundamental aspects of calculus and algebra.
- Each term of a polynomial is made up of a coefficient and a variable raised to an exponent.
- For \(f(x) = 4x^2\): the term \(4x^2\) has a coefficient 4, and the power of 2 indicates it's a quadratic polynomial.
- Polynomial functions are smooth and continuous, making them easily differentiable.
differentiation steps
Differentiation involves finding the derivative of a function, and it can be broken down into systematic steps to simplify the process, especially when using the limit definition. Let's recap the differentiation steps used for \(f(x) = 4x^2\):
1. **Substitution:** Quote the function into the derivative formula: \[ f'(x) = \lim_{h \to 0} \frac{4(x+h)^2 - 4x^2}{h} \] 2. **Expansion:** Distribute and expand \((x+h)^2\) to become \(x^2 + 2xh + h^2\). Substitute back: \[ f'(x) = \lim_{h \to 0} \frac{4x^2 + 8xh + 4h^2 - 4x^2}{h} \] 3. **Simplification:** Cancel out like terms \(4x^2\): \[ f'(x) = \lim_{h \to 0} \frac{8xh + 4h^2}{h} \] 4. **Factorization:** Factor out \(h\) from the reduced expression: \[ f'(x) = \lim_{h \to 0} \frac{h(8x + 4h)}{h} \] 5. **Limit Calculation:** Cancel \(h\) and calculate the limit as \(h\) approaches zero: \[ f'(x) = 8x \]
These steps ensure that we find the derivative correctly, making them a powerful technique for evaluating how functions behave at any given point.
1. **Substitution:** Quote the function into the derivative formula: \[ f'(x) = \lim_{h \to 0} \frac{4(x+h)^2 - 4x^2}{h} \] 2. **Expansion:** Distribute and expand \((x+h)^2\) to become \(x^2 + 2xh + h^2\). Substitute back: \[ f'(x) = \lim_{h \to 0} \frac{4x^2 + 8xh + 4h^2 - 4x^2}{h} \] 3. **Simplification:** Cancel out like terms \(4x^2\): \[ f'(x) = \lim_{h \to 0} \frac{8xh + 4h^2}{h} \] 4. **Factorization:** Factor out \(h\) from the reduced expression: \[ f'(x) = \lim_{h \to 0} \frac{h(8x + 4h)}{h} \] 5. **Limit Calculation:** Cancel \(h\) and calculate the limit as \(h\) approaches zero: \[ f'(x) = 8x \]
These steps ensure that we find the derivative correctly, making them a powerful technique for evaluating how functions behave at any given point.