Chapter 3: Problem 290
Use the given values to find \(\left(f^{-1}\right)^{\prime}(a)\). $$ f(6)=2, f^{\prime}(6)=\frac{1}{3}, a=2 $$
Short Answer
Expert verified
\( \left(f^{-1}\right)^{\prime}(2) = 3 \).
Step by step solution
01
Understand the Problem
We need to find the derivative of the inverse function at a given point, specifically \( \left(f^{-1}\right)^{\prime}(a) \). We're given values \( f(6)=2 \), \( f^{\prime}(6)=\frac{1}{3} \), and \( a=2 \).
02
Apply Inverse Function Derivative Rule
The rule for the derivative of an inverse function states: if \( f(x) \) is differentiable and its inverse \( f^{-1}(x) \) exists and is differentiable at \( a \), then \( \left(f^{-1}\right)^{\prime}(a) = \frac{1}{f^{\prime}(f^{-1}(a))} \). We need to find \( f^{-1}(2) \) first.
03
Determine \( f^{-1}(a) \)
Given \( f(6) = 2 \), this implies that \( f^{-1}(2) = 6 \). Because applying \( f \) to 6 returns 2, \( f^{-1}(2) \) must return 6.
04
Substitute Values into Derivative Rule
We substitute \( f^{-1}(2) = 6 \) into the derivative formula: \( \left(f^{-1}\right)^{\prime}(2) = \frac{1}{f^{\prime}(6)} \).
05
Calculate the Final Answer
Using the given value \( f^{\prime}(6) = \frac{1}{3} \), substitute to find \( \left(f^{-1}\right)^{\prime}(2) = \frac{1}{\frac{1}{3}} = 3 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative of Inverse Functions
The derivative of inverse functions is a pivotal concept in calculus. When you have a function and its inverse, you might wonder how their derivatives relate to one another. The rule for the derivative of an inverse function provides a neat solution. If a function \( f(x) \) is continuous and differentiable, and its inverse \( f^{-1}(x) \) exists, the relationship between their derivatives can be expressed as:
- \( \left( f^{-1} \right)^{\prime}(a) = \frac{1}{f^{\prime}(f^{-1}(a))} \).
Inverse Function
An inverse function essentially "undoes" what the original function does. If function \( f \) maps a value \( x \) to \( y \), the inverse function \( f^{-1} \) maps \( y \) back to \( x \). Understanding this concept is essential when dealing with derivative problems involving inverse functions.
- The inverse exists if, for every output of the original function, there's exactly one corresponding input.
- The role of the inverse function is to reverse the effect of the function.
Calculus Problem-Solving
Solving calculus problems requires a systematic approach. For the exercise at hand, we're tasked with finding the derivative of the inverse function at a given point. Here's a simplified approach:
- Identify the given values and what is required. In this case, \( f(6) = 2 \), \( f^{\prime}(6) = \frac{1}{3} \), and \( a = 2 \).
- Determine the inverse value, such as \( f^{-1}(2) = 6 \) since \( f(6) = 2 \).
- Apply the derivative of inverse function formula: \( \left( f^{-1} \right)^{\prime}(a) = \frac{1}{f^{\prime}(f^{-1}(a))} \).
- Plug in the known values and compute the result: \( \left( f^{-1} \right)^{\prime}(2) = \frac{1}{\frac{1}{3}} = 3 \).
Function Derivatives
Derivatives are a fundamental concept in calculus, representing the rate of change or slope of a function at any given point. When dealing with function derivatives, especially with inverse functions, there are certain nuances to keep in mind.
- The derivative of a function \( f \) at a point is denoted as \( f^{\prime}(x) \).
- Knowing the derivatives of base functions can help in calculating more complex derivatives.