Chapter 3: Problem 233
For the following exercises, find \(\frac{d y}{d x}\) for each function. $$y=(\tan x+\sin x)^{-3}$$
Short Answer
Expert verified
\(\frac{dy}{dx} = -3(\tan x + \sin x)^{-4}(\sec^2 x + \cos x)\)
Step by step solution
01
Identify the function type
The given function is a composition of two functions: an inner function and an outer function. The inner function is \(u = \tan x + \sin x\) and the outer function is \(y = u^{-3}\)
02
Find the derivative of the inner function
Differentiate the inner function \(u = \tan x + \sin x\). The derivative of \(\tan x\) is \(\sec^2 x\), and the derivative of \(\sin x\) is \(\cos x\). Thus, \(\frac{du}{dx} = \sec^2 x + \cos x\).
03
Find the derivative of the outer function
The outer function is \(y = u^{-3}\). Using the power rule, the derivative is \(\frac{dy}{du} = -3u^{-4}\).
04
Apply the chain rule
To find \(\frac{dy}{dx}\), apply the chain rule: \(\frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx}\). Substitute \(\frac{dy}{du} = -3u^{-4}\) and \(\frac{du}{dx} = \sec^2 x + \cos x\).
05
Substitute the inner function back in
Replace \(u\) in \(-3u^{-4}\) with \(\tan x + \sin x\). This gives \(\frac{dy}{dx} = -3(\tan x + \sin x)^{-4}(\sec^2 x + \cos x)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental concept in calculus used to differentiate composite functions. A composite function is when one function is placed inside another. In our example, we have an outer function and an inner function. The inner function is:
- \(u = \tan x + \sin x\)
- \(y = u^{-3}\).
- \(\frac{dy}{du}\) is the derivative of the outer function with respect to \(u\),
- \(\frac{du}{dx}\) is the derivative of the inner function with respect to \(x\).
Power Rule
The power rule is a basic technique in differentiation used to find the derivative of functions in the form \(y = x^n\), where \(n\) is a real number. According to the power rule, the derivative of \(y = x^n\) with respect to \(x\) is: \[ \frac{d}{dx} x^n = nx^{n-1} \] In the current exercise, this rule is applied to the outer function, which is \(y = u^{-3}\). Using the power rule, we find its derivative with respect to \(u\) as follows:
- \(\frac{dy}{du} = -3u^{-4}\).
Trigonometric Functions
Trigonometric functions play a critical role in calculus because they often appear in the context of waveforms, circles, and other periodic phenomena. In this exercise, the inner function \(u = \tan x + \sin x\) includes two commonly used trigonometric functions: tangent and sine.
- The derivative of \(\tan x\) is \(\sec^2 x\). This derivative arises because of the unique relationship between tangent and secant functions.
- The derivative of \(\sin x\) is \(\cos x\), resulting from the fundamental properties of sine and cosine relationships.