Chapter 2: Problem 191
In the following exercises, use the precise definition of limit to prove the given limits. $$\lim _{x \rightarrow 0} x^{4}=0$$
Short Answer
Expert verified
The limit is confirmed: \( \lim_{x \to 0} x^4 = 0 \) with \( \delta = \varepsilon^{1/4} \).
Step by step solution
01
Identify the Epsilon Definition
The epsilon (\( \varepsilon \)) definition of a limit states that for a function \(f(x)\), \( \lim_{x \to a} f(x) = L \) if for every \( \varepsilon > 0\), there exists a \( \delta > 0\) such that whenever \( 0 < |x - a| < \delta\), it follows that \( |f(x) - L| < \varepsilon \). For this problem, we have \( \lim_{x \to 0} x^4 = 0 \). This means for every \( \varepsilon > 0\), there should exist a \( \delta > 0\) such that \( |x^4 - 0| < \varepsilon \) whenever \( 0 < |x| < \delta \).
02
Simplify the Expression
To start, recognize that \( |x^4 - 0| = |x^4| = x^4 \). We need to ensure that this is less than \( \varepsilon \) whenever \( 0 < |x| < \delta \). Thus, our goal boils down to making sure that \( x^4 < \varepsilon \).
03
Select an Appropriate Delta
Since \( x^4 < \varepsilon \), consider the relationship for \( x \), which gives \( |x| < \varepsilon^{1/4} \). Hence, if we choose \( \delta = \varepsilon^{1/4} \), then for \( 0 < |x| < \delta \), we will have \( x^4 < \varepsilon \).
04
Prove the Choice of Delta
For the choice of \( \delta = \varepsilon^{1/4} \), we verify that whenever \( 0 < |x| < \delta \), we get \( |x| < \varepsilon^{1/4} \). Consequently, \( x^4 = |x|^4 < (\varepsilon^{1/4})^4 = \varepsilon \). This shows the limit definition conditions are satisfied.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Epsilon-Delta Definition
The epsilon-delta definition is a foundational concept in calculus, widely used to rigorously define the limit of a function. It's a way of saying that as the input of a function approaches a certain value, the output of the function approaches a certain limit. This approach hinges on two small positive numbers: epsilon (\( \varepsilon \)) and delta (\( \delta \)).Here’s how it works:
- \( \varepsilon \) is any positive number, no matter how small, representing the desired closeness between the function value and the limit.
- \( \delta \) is a positive number that corresponds to \( \varepsilon \), dictating how close \( x \) (the input) needs to be to the number you're approaching.
Calculus Limits
In calculus, a limit is a fundamental concept used to describe the behavior of a function as its argument approaches a particular point. The limit of a function at a point ensures that the function approaches a particular value as closely as desired, given the right proximity.Here's an overview:
- The formal notation \( \lim_{x \to a} f(x) = L \) states that as \( x \) approaches \( a \), \( f(x) \) gets arbitrarily close to \( L \).
- Limits are crucial for defining derivatives and integrals, which are the core tools of calculus.
Proof of Limits
Proving limits using the epsilon-delta definition involves a clear, step-by-step approach. The goal is to demonstrate that for every epsilon (\( \varepsilon \)), there exists a delta (\( \delta \)) that confines the function's result within \( \varepsilon \) of the proposed limit when the input is near the point of interest.Here's a step-by-step breakdown as applied to \( \lim_{x \rightarrow 0} x^{4}=0 \):
- Start by identifying that \( |f(x) - L| = |x^4 - 0| = |x^4| \) must be less than any \( \varepsilon \).
- Our task becomes selecting \( \delta \) such that whenever \( 0 < |x| < \delta \), then \( x^4 < \varepsilon \).
- This is simplified by recognizing \( |x| < \varepsilon^{1/4} \). Therefore, choosing \( \delta = \varepsilon^{1/4} \) works perfectly.
- The verification step assures that whenever \( 0 < |x| < \varepsilon^{1/4} \), \( x^4 = |x|^4 < (\varepsilon^{1/4})^4 = \varepsilon \), satisfying the limit conditions.