Chapter 2: Problem 182
The following graph of the function \(f\) satisfies $$\lim _{x \rightarrow 3} f(x)=-1 .$$ In the following exercises, determine a value of \(\delta>0\) that satisfies each statement. If \(0<|x-3|<\delta,\) then \(|f(x)+1|<1\)
Short Answer
Expert verified
Choose \( \delta = 0.5 \) based on the graph analysis.
Step by step solution
01
Understanding the Limit
The limit provided in the problem, \( \lim _{x \rightarrow 3} f(x)=-1 \), tells us that as \( x \) approaches 3, the values of \( f(x) \) get arbitrarily close to -1. This means for every \( \varepsilon > 0 \), there exists a \( \delta > 0 \) such that if \( 0 < |x - 3| < \delta \), then \( |f(x) + 1| < \varepsilon \).
02
Analyzing the Required Condition
The problem asks us to find a specific \( \delta > 0 \) such that whenever \( 0 < |x - 3| < \delta \), \( |f(x) + 1| < 1 \). So, we set \( \varepsilon = 1 \) and need to determine a suitable \( \delta \) that satisfies this requirement.
03
Choosing an Appropriate Delta
Since \( \varepsilon = 1 \), we need \( |f(x) + 1| < 1 \). This inequality is equivalent to saying \(-2 < f(x) < 0\). To find \( \delta \), we need to look at the graph and determine how close \( x \) needs to be to 3 in order for \( f(x) \) to stay within the interval \(-2 < f(x) < 0\).
04
Confirming Delta from Graph
Inspect the graph to see how \( f(x) \) behaves as \( x \) approaches 3. Check the interval around 3 where \( f(x) \) stays within \(-2 < f(x) < 0\). Suppose the graph shows that if \( x \) is within a distance of \( 0.5 \) from 3, \( f(x) \) does not go beyond -2 or 0. Thus, we can choose \( \delta = 0.5\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Delta-epsilon definition
When dealing with limits, such as \( \lim _{x \rightarrow 3} f(x)=-1 \), we often use the delta-epsilon definition to formally articulate how limits work. This definition hinges on two Greek letters, \( \varepsilon \) (epsilon) and \( \delta \) (delta). Here's what they do:
This relationship can be expressed as: If \( 0 < |x - 3| < \delta \), then \( |f(x) + 1| < \varepsilon \). This confirms that as \( x \) nears 3 by less than \( \delta \), \( f(x) \) gets ever closer to -1 by less than \( \varepsilon \). The beauty of this concept lies in its emphasis on precision, defining the behavior around specific points on a function.
- \( \varepsilon \) represents how close we want \( f(x) \) to get to the limit \( L = -1 \).
- \( \delta \) signifies the closeness of \( x \) to the point where the limit is evaluated, in this case, 3.
This relationship can be expressed as: If \( 0 < |x - 3| < \delta \), then \( |f(x) + 1| < \varepsilon \). This confirms that as \( x \) nears 3 by less than \( \delta \), \( f(x) \) gets ever closer to -1 by less than \( \varepsilon \). The beauty of this concept lies in its emphasis on precision, defining the behavior around specific points on a function.
Continuity
Continuity is closely linked with limits and involves examining how smoothly a function operates through its domain. A function \( f(x) \) is continuous at a point \( x = c \) if:
In our problem, we're given \( \lim _{x \rightarrow 3} f(x)=-1 \). This statement affirms that \( f(x) \) approaches -1 as \( x \) approaches 3, but not necessarily that \( f(x) = -1 \) at \( x = 3 \). Continuity concerns us because it verifies the unbroken nature of the function around such points.
If indeed \( f(3) = -1 \), coupled with the fact that \( \lim_{x \to 3} f(x) \) equals -1, it would imply that \( f(x) \) seamlessly passes through \(-1\) at point 3, thereby making it continuous at that point.
Finally, grasping continuity is crucial in recognizing subtle shifts and stable segments in the graph, reinforcing the behavior analyzed in delta-epsilon terms.
- \( f(c) \) is defined.
- \( \lim_{x \to c} f(x) \) exists.
- \( \lim_{x \to c} f(x) = f(c) \).
In our problem, we're given \( \lim _{x \rightarrow 3} f(x)=-1 \). This statement affirms that \( f(x) \) approaches -1 as \( x \) approaches 3, but not necessarily that \( f(x) = -1 \) at \( x = 3 \). Continuity concerns us because it verifies the unbroken nature of the function around such points.
If indeed \( f(3) = -1 \), coupled with the fact that \( \lim_{x \to 3} f(x) \) equals -1, it would imply that \( f(x) \) seamlessly passes through \(-1\) at point 3, thereby making it continuous at that point.
Finally, grasping continuity is crucial in recognizing subtle shifts and stable segments in the graph, reinforcing the behavior analyzed in delta-epsilon terms.
Graphical analysis
Graphical analysis is a fantastic tool for visualizing what's going on with functions and limits. By interpreting a function’s behavior on a graph, we see the "story" of \( f(x) \) as it converges to a limit.
A graph presents the function \( f(x) \) and allows us to check the closeness of \( x \) values around 3. This gives insight into how \( f(x) \) behaves near this value, illustrating whether the function reaches or stays within certain bounds, such as between \(-2\) and \(0\).
To implement this in practice, focus on:
This harmony of numerical precision and graphical intuition culminates in a full-bodied understanding of function limits and behavior, preparing you to tackle more complex scenarios with confidence.
A graph presents the function \( f(x) \) and allows us to check the closeness of \( x \) values around 3. This gives insight into how \( f(x) \) behaves near this value, illustrating whether the function reaches or stays within certain bounds, such as between \(-2\) and \(0\).
To implement this in practice, focus on:
- Observing the interval \( (3 - \delta, 3 + \delta) \) on the x-axis to see where \( f(x) \) lies within the target zone \(-2 < f(x) < 0 \).
- Identifying patterns and potential outliers that may disrupt the expected behavior.
This harmony of numerical precision and graphical intuition culminates in a full-bodied understanding of function limits and behavior, preparing you to tackle more complex scenarios with confidence.