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\(h(x)=\left\\{\begin{array}{ll}x^{2}-2 x+1, & x<2 \\ 3-x, & x \geq 2\end{array}\right.\) a. \(\lim _{x \rightarrow 2^{-}} h(x)\) b. \(\lim _{x \rightarrow 2^{+}} h(x)\)

Short Answer

Expert verified
Both left-hand and right-hand limits equal 1 as \(x\) approaches 2.

Step by step solution

01

Identify the Left-Hand Limit Function

For the left-hand limit as \(x\) approaches 2 from the left (\(x \rightarrow 2^{-}\)), we use the function defined for \(x < 2\), which is \(h(x) = x^{2}-2x+1\).
02

Substitute into the Left-Hand Function

To find \(\lim _{x \rightarrow 2^{-}} h(x)\), we substitute \(x = 2\) into the expression \(x^{2} - 2x + 1\). This gives us \((2)^{2} - 2 \cdot 2 + 1\).
03

Calculate Left-Hand Limit

Perform the calculation: \((2)^{2} - 2 \cdot 2 + 1 = 4 - 4 + 1 = 1\). Thus, \(\lim _{x \rightarrow 2^{-}} h(x) = 1\).
04

Identify the Right-Hand Limit Function

For the right-hand limit as \(x\) approaches 2 from the right (\(x \rightarrow 2^{+}\)), we use the function defined for \(x \geq 2\), which is \(h(x) = 3-x\).
05

Substitute into the Right-Hand Function

To find \(\lim _{x \rightarrow 2^{+}} h(x)\), we substitute \(x = 2\) into the expression \(3 - x\). This gives us \(3 - 2\).
06

Calculate Right-Hand Limit

Perform the calculation: \(3 - 2 = 1\). Thus, \(\lim _{x \rightarrow 2^{+}} h(x) = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Left-Hand Limits
A left-hand limit examines the behavior of a function as it approaches a certain value from the left side. For piecewise functions, we use the segment defined for values less than the point of interest when determining a left-hand limit. For instance, if we look at the exercise with function \(h(x)\), to calculate \(\lim_{x \rightarrow 2^{-}} h(x)\), we use the expression given for \(x < 2\), which is \(x^2 - 2x + 1\). By substituting \(x = 2\) into this quadratic equation, we derive:
  • Substitution: \((2)^2 - 2 \times 2 + 1\)
  • Calculation: \(4 - 4 + 1 = 1\)
Thus, the left-hand limit as \(x\) approaches 2 is 1. This process confirms continuity from the left even when the function switches formulas at \(x = 2\).
Exploring Right-Hand Limits
The right-hand limit is concerned with how a function behaves as it nears a certain value from the right side. For piecewise functions, we select the part defined for the specified range inclusive of or exceeding the point.In our example, to find \(\lim_{x \rightarrow 2^{+}} h(x)\), we apply the segment for \(x \geq 2\) which is \(3 - x\). We then substitute \(x = 2\) into this linear equation:
  • Substitution: \(3 - 2\)
  • Calculation: \(3 - 2 = 1\)
After calculating, we confirm \(\lim_{x \rightarrow 2^{+}} h(x) = 1\). By matching this result with the left-hand counterpart, we determine the function's behavior from both sides of \(x = 2\).
Understanding Continuity
Continuity of a function at a certain point means its left-hand and right-hand limits are equal and the function value itself is defined and matches these limits. In a piecewise function, demonstrating continuity involves ensuring the behavior from both sides of a point converges.For the piecewise function \(h(x)\), the limits on both sides for \(x = 2\) are calculated as:
  • Left-hand limit: \(1\)
  • Right-hand limit: \(1\)
With both limits equating to 1, we see that \(h(2)\) also equals 1 when evaluated from either function component. Thus, continuity at \(x = 2\) is validated by the convergence of both directional limits with the function's actual value at this point. This ensures a seamless transition across the piecewise boundary at the evaluated point, indicating the function does not "break" at \(x = 2\).

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