Chapter 1: Problem 58
[T] Use a graphing calculator to graph the half-circle \(y=\sqrt{25-(x-4)^{2}} .\) Then, use the INTERCEPT feature to find the value of both the \(x\) - and \(y\) -intercepts.
Short Answer
Expert verified
X-intercepts at -1 and 9; Y-intercept at 3.
Step by step solution
01
Understand the Equation
The given equation is \( y = \sqrt{25 - (x-4)^2} \). This represents the top half of a circle centered at \((4, 0)\) with radius 5. The circle's full equation would be \((x-4)^2 + y^2 = 25\).
02
Set Up the Graphing Calculator
On your graphing calculator, enter the function \( y = \sqrt{25 - (x-4)^2} \). This will graph the top half of the circle. Ensure the window is set to show a range around the center (4,0) to capture the entire semicircle.
03
Identify the X-Intercept
Using the graph on the calculator, enable the 'INTERCEPT' feature and navigate to find where the graph crosses the x-axis. One x-intercept will be to the left of the center (4,0) and the other to the right.
04
Calculate the X-Intercepts
Set \( y = 0 \) in the equation to solve for \( x \): \( 0 = \sqrt{25 - (x-4)^2} \). Squaring both sides, we get: \( 25 = (x-4)^2 \). Solving this gives \( x-4 = \pm 5 \). Thus, the x-intercepts are at \( x = 9 \) and \( x = -1 \).
05
Identify the Y-Intercept
Using the graph, observe where it crosses the y-axis. There is only one value where the graph will intersect the y-axis.
06
Calculate the Y-Intercept
Setting \( x = 0 \) in the equation, solve for \( y \): \( y = \sqrt{25 - (0-4)^2} = \sqrt{25-16} = \sqrt{9} = 3 \). Therefore, the y-intercept is at \( y = 3 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Circle Equation
To understand the concept of a half-circle equation, it's helpful to start with the full circle equation. A circle centered at
In practical terms, drawing this graph will yield a semicircle that sits above the x-axis. The equation includes a square root because we're only interested in the positive sqrt values (hence, the top half). This equation omits any negative y-values, effectively slicing the circle in half horizontally.
- (4, 0)
- with a radius of 5,
- \((x-4)^2 + y^2 = 25\).
- \(y = \sqrt{25 - (x-4)^2}\),
In practical terms, drawing this graph will yield a semicircle that sits above the x-axis. The equation includes a square root because we're only interested in the positive sqrt values (hence, the top half). This equation omits any negative y-values, effectively slicing the circle in half horizontally.
X-Intercepts
X-intercepts are the points where the curve crosses the x-axis. To find these, we set
- \(y = 0\)
- \(y = \sqrt{25 - (x-4)^2}\),
- \(y = 0\)
- \((x-4)^2 = 25\).
- \(x-4 = \pm 5\).
- \(x = 9\)
- and
- \(x = -1\),
Y-Intercept
The y-intercept is the point where the graph crosses the y-axis. To uncover this point, we set
- \(x = 0\)
- \(y = \sqrt{25 - (0-4)^2}\)
- \(y = \sqrt{25 - 16} = \sqrt{9}\).
- \(y = 3\),
Graphing Techniques
Graphing a complex equation like a half-circle requires precise techniques. A graphing calculator is invaluable here, enabling you to visualize complicated functions swiftly. It's important to configure your graphing calculator correctly:
- Enter the Function: Input \(y = \sqrt{25 - (x-4)^2}\) into your calculator.
- Set the Window: Adjust your viewing window to ensure the center
- (4, 0) is visible, along with a wide enough range on both axes.