Chapter 1: Problem 37
For the following exercises, for each pair of functions, find a. \(f+g\) b. \(f-g\) c. \(f \cdot g\) d. \(f / g .\) Determine the domain of each of these new functions. $$ f(x)=x-8, g(x)=5 x^{2} $$
Short Answer
Expert verified
f+g = 5x^2 + x - 8; f-g = -5x^2 + x - 8; f⋅g = 5x^3 - 40x^2; f/g = (x-8)/(5x^2), domain: all x≠0.
Step by step solution
01
Find f+g
To find \( f + g \), we simply add the two functions together: \[(f+g)(x) = f(x) + g(x) = (x - 8) + 5x^2 = 5x^2 + x - 8.\] The domain of \( f + g \) is all real numbers since both \( f(x) \) and \( g(x) \) are defined for all \( x \).
02
Find f-g
To find \( f - g \), we subtract \( g(x) \) from \( f(x) \): \[(f-g)(x) = f(x) - g(x) = (x - 8) - 5x^2 = -5x^2 + x - 8.\] The domain of \( f - g \) is all real numbers, similar to \( f + g \).
03
Find fâ‹…g
To find \( f \cdot g \), we multiply the functions: \[(f \cdot g)(x) = f(x) \cdot g(x) = (x - 8)(5x^2) = 5x^3 - 40x^2.\] The domain of \( f \cdot g \) is all real numbers, as \( f(x) \) and \( g(x) \) are both polynomials and have domains of all real numbers.
04
Find f/g
To find \( \frac{f}{g} \), divide \( f(x) \) by \( g(x) \): \[\left( \frac{f}{g} \right)(x) = \frac{x - 8}{5x^2}.\]The domain of \( \frac{f}{g} \) consists of all real numbers except where \( g(x) = 0 \), which happens when \( x = 0 \). Therefore, the domain is all real numbers except \( x = 0 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Addition
Function addition is the process of creating a new function by adding two existing functions together. For two functions \( f(x) \) and \( g(x) \), the sum, represented as \( (f+g)(x) \), is obtained by simply adding the outputs of \( f \) and \( g \) for each input \( x \). For example, if \( f(x) = x - 8 \) and \( g(x) = 5x^2 \), then:
- \( (f+g)(x) = f(x) + g(x) = (x - 8) + 5x^2 = 5x^2 + x - 8 \)
Function Subtraction
Function subtraction works similarly to addition, except you subtract one function from another. With \( f(x) \) and \( g(x) \), subtraction is shown as \( (f-g)(x) \). This involves taking the value of \( g(x) \) away from \( f(x) \) for each input \( x \). For the functions \( f(x) = x - 8 \) and \( g(x) = 5x^2 \):
- \( (f-g)(x) = f(x) - g(x) = (x - 8) - 5x^2 = -5x^2 + x - 8 \)
Function Multiplication
Function multiplication combines functions by multiplying their outputs for each input \( x \). The notation for this is \( (f \cdot g)(x) \). Given \( f(x) = x - 8 \) and \( g(x) = 5x^2 \), the process is:
- \( (f \cdot g)(x) = f(x) \cdot g(x) = (x - 8)(5x^2) = 5x^3 - 40x^2 \)
Function Division
Function division involves dividing the output of one function by the output of another and is represented as \( \left( \frac{f}{g} \right)(x) \). This operation introduces more complexity because one must be wary of dividing by zero. For \( f(x) = x - 8 \) and \( g(x) = 5x^2 \):
- \( \left( \frac{f}{g} \right)(x) = \frac{x - 8}{5x^2} \)
Domain of Functions
The domain of a function refers to all possible inputs (or \( x \) values) for which the function is defined. It can vary depending on the operations involved. To determine the domain, consider situations in which the function fails to produce a valid output.
The function \( \left( \frac{f}{g} \right)(x) \) has a domain of all real numbers except where \( g(x) = 0 \). Here, \( \left( \frac{f}{g} \right)(x) \) is undefined at \( x = 0 \). Thus, it's crucial to evaluate functions before assuming they are well-defined across all real numbers.
- For addition, subtraction, and multiplication of polynomials, the domain is all real numbers.
- When division is involved, the domain is restricted by the values that make the denominator zero, which must be excluded from the domain.
The function \( \left( \frac{f}{g} \right)(x) \) has a domain of all real numbers except where \( g(x) = 0 \). Here, \( \left( \frac{f}{g} \right)(x) \) is undefined at \( x = 0 \). Thus, it's crucial to evaluate functions before assuming they are well-defined across all real numbers.