Chapter 1: Problem 24
Set up a table to sketch the graph of each function using the following values: \(x=-3,-2,-1,0,1,2,3\) \(\quad f(x)=\frac{1}{2} x+1\)
Short Answer
Expert verified
Sketch a table with \( x \) values and corresponding \( f(x) \) values.
Step by step solution
01
Identify the function
The given function is the linear function \( f(x) = \frac{1}{2}x + 1 \). This equation is in the slope-intercept form \( y = mx + b \), where \( m = \frac{1}{2} \) and \( b = 1 \).
02
Create a table for x and f(x)
We'll evaluate the function \( f(x) \) for each specified \( x \) value: \(-3, -2, -1, 0, 1, 2, 3\). We'll fill in the table with these \( x \) values and their corresponding \( f(x) \) values.
03
Calculate f(x) for each x value
- For \( x = -3 \): \( f(-3) = \frac{1}{2}(-3) + 1 = -\frac{3}{2} + 1 = -\frac{1}{2} \)- For \( x = -2 \): \( f(-2) = \frac{1}{2}(-2) + 1 = -1 + 1 = 0 \)- For \( x = -1 \): \( f(-1) = \frac{1}{2}(-1) + 1 = -\frac{1}{2} + 1 = \frac{1}{2} \)- For \( x = 0 \): \( f(0) = \frac{1}{2}(0) + 1 = 1 \)- For \( x = 1 \): \( f(1) = \frac{1}{2}(1) + 1 = \frac{1}{2} + 1 = \frac{3}{2} \)- For \( x = 2 \): \( f(2) = \frac{1}{2}(2) + 1 = 1 + 1 = 2 \)- For \( x = 3 \): \( f(3) = \frac{1}{2}(3) + 1 = \frac{3}{2} + 1 = \frac{5}{2} \)
04
Record the values in the table
The table to sketch the graph is as follows:\[\begin{array}{|c|c|}\hlinex & f(x) \\hline-3 & -\frac{1}{2} \-2 & 0 \-1 & \frac{1}{2} \0 & 1 \1 & \frac{3}{2} \2 & 2 \3 & \frac{5}{2} \\hline\end{array}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form is an important way to describe linear functions. It is expressed as \( y = mx + b \). Here, \( m \) is the slope, and \( b \) is the y-intercept. The slope of a line, \( m \), indicates how steep the line is.
- For example, a slope of \( \frac{1}{2} \) suggests that for every increase of 1 in \( x \), \( y \) increases by \( \frac{1}{2} \).
- Y-intercept, \( b \), is the point where the line crosses the y-axis. If \( b = 1 \), the line crosses the y-axis at \( y = 1 \).
Graph Sketching
Graph sketching is a visual representation of the linear function. It involves plotting points calculated from the function and then drawing the line that connects these points.Begin by choosing specific \( x \) values. Here, they are \(-3, -2, -1, 0, 1, 2, 3\). Calculate \( f(x) \) for each of these x-values:
- For \( x = -3 \), \( f(-3) = -\frac{1}{2} \)
- For \( x = -2 \), \( f(-2) = 0 \)
- For \( x = -1 \), \( f(-1) = \frac{1}{2} \)
- For \( x = 0 \), \( f(0) = 1 \)
- For \( x = 1 \), \( f(1) = \frac{3}{2} \)
- For \( x = 2 \), \( f(2) = 2 \)
- For \( x = 3 \), \( f(3) = \frac{5}{2} \)
Evaluating Functions
Evaluating functions means finding the value of \( f(x) \) for specific \( x \) values. This process is crucial for understanding how input \( x \) relates to output \( f(x) \).Consider the function \( f(x) = \frac{1}{2}x + 1 \). To evaluate, substitute each x-value into the equation:
- First, multiply \( x \) by \( \frac{1}{2} \).
- Then, add 1 to the result.