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Use the Comparison Test for Convergence to show that the given series converges. State the series that you use for comparison and the reason for its convergence. $$ \sum_{n=1}^{\infty} \frac{2^{n}}{n 3^{n}} $$

Short Answer

Expert verified
The series \( \sum_{n=1}^{\infty} \frac{2^{n}}{n 3^{n}} \) converges by comparison with the convergent geometric series \( \sum_{n=1}^{\infty} \left( \frac{2}{3} \right)^n \).

Step by step solution

01

Identify the form of the given series

The given series is \( \sum_{n=1}^{\infty} \frac{2^{n}}{n 3^{n}} \). Notice that the terms of the series can be rewritten as \( \frac{1}{n} \left( \frac{2}{3} \right)^n \).
02

Choose appropriate series for comparison

We will compare the given series with the geometric series \( \sum_{n=1}^{\infty} \left( \frac{2}{3} \right)^n \). The series \( \sum_{n=1}^{\infty} \left( \frac{2}{3} \right)^n \) is a geometric series with ratio \( r = \frac{2}{3} \), which is less than 1, and thus is convergent.
03

Apply the Comparison Test

For \( n \geq 1 \), we have \( \frac{2^n}{n3^n} = \frac{1}{n} \left( \frac{2}{3} \right)^n \). As \( n \to \infty \), the expression \( \frac{1}{n} \to 0 \), implying \( \frac{1}{n} \left( \frac{2}{3} \right)^n < \left( \frac{2}{3} \right)^n \). Because \( \sum \left( \frac{2}{3} \right)^n \) is convergent, by the Comparison Test, \( \sum \frac{2^n}{n3^n} \) also converges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Convergence
A series is a sum of terms that can go on indefinitely. Determining if this infinite sum gets close to a specific value (converges) or not (diverges) is called series convergence. Understanding whether a series converges is crucial in mathematical calculations, especially in calculus and higher-level math.
To check for convergence, we often compare a series to another series whose behavior we already know. Think about a series as a never-ending accumulation of numbers. If adding each number eventually stops changing the total by much, we say the series converges. Conversely, if the sum keeps getting larger without bound, it diverges.
Convergent series get close to a specific limit, like turning on a tap and waiting for a vase to fill and staying full. Divergent series would be like trying to fill a bucket with no bottom—the water never settles into a contained space. This concept plays a big role in ensuring calculations in real-world scenarios, such as in physics or engineering, are accurate.
Geometric Series
A geometric series is a type of series where each term is a fixed multiple of the previous one. You might see them and their convergence properties used a lot because they're simple yet powerful.
A basic example is series of the form:
  • \( a + ar + ar^2 + ar^3 + \ldots \)
where \( a \) is the first term and \( r \) is the common ratio.
Knowing if this series converges depends heavily on the value of \( r \). If the absolute value of \( r \) is less than 1, the series converges to:\[ S = \frac{a}{1-r} \]If \( |r| \geq 1 \), the series diverges, which means the series' total can’t settle towards any limit. Geometric series are often used in comparison tests because they’re straightforward and can easily highlight the behavior of other more complex series. Like analyzing a stream’s flow by comparing it to a steady current, geometric series let mathematicians quickly assess convergence of similar series.
Convergence Tests
Convergence tests are tools that mathematicians use to determine if a series converges or diverges. Among these, the Comparison Test is particularly useful when dealing with more complex series.
The idea here is to weigh your series against a series you already know converges or diverges. If your unknown series is 'lighter' than something that converges, it converges too. Conversely, if it’s 'heavier' than a divergent, it surely diverges. Think of it as checking new scales against a known standard.
To perform a Comparison Test, follow these general steps:
  • Select a benchmark series that is similar and whose convergence is known.
  • Relate the terms of your series to the benchmark to show they are smaller or larger.
  • Use these size comparisons to conclude about the unknown series' convergence.
This test is especially valuable because it doesn't require computing the series' sum directly, offering a simpler path to figuring out convergence with just a bit of strategic comparison and some clever logic.

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