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The partial sum \(S_{N}=\sum_{n=1}^{N} a_{n}\) of an infinite series \(\sum_{n=1}^{\infty} a_{n}\) is given. Determine the value of the infinite series. $$ S_{N}=(N+1) /(N+4) $$

Short Answer

Expert verified
The sum of the infinite series is 1.

Step by step solution

01

Identify the Limit of the Partial Sum

The first step is to determine the limit of the partial sum \(S_N\) as \(N\) approaches infinity. This limit, if it exists, will give us the sum of the infinite series. Here, the partial sum is given as \(S_N = \frac{N+1}{N+4}\).
02

Simplify the Expression for the Limit

To find \(\lim_{N \to \infty} S_N\), simplify \(\frac{N+1}{N+4}\) by dividing both the numerator and the denominator by \(N\), the highest power of \(N\) present.\[\frac{N+1}{N+4} = \frac{1 + \frac{1}{N}}{1 + \frac{4}{N}}\]
03

Evaluate the Limit as N Approaches Infinity

Evaluate the limit by substituting \(N\to\infty\), which simplifies the terms \(\frac{1}{N}\) and \(\frac{4}{N}\) to zero.\[\lim_{N \to \infty} \frac{1 + \frac{1}{N}}{1 + \frac{4}{N}} = \frac{1+0}{1+0} = 1\]
04

Conclude the Sum of the Infinite Series

Since the limit of the partial sum \(S_N\) as \(N\) approaches infinity converges to 1, the sum of the infinite series \(\sum_{n=1}^{\infty} a_n\) is 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Sum
A partial sum is essentially the summation of the initial segment of a series. In the context of an **infinite series**, we often start by considering a finite number of terms, say the first **N** terms, to grasp the behavior of the series. This finite sum is known as the partial sum, denoted as \( S_N \).
In our problem, the partial sum is given by the formula \( S_N = \frac{N+1}{N+4} \). This expression helps us understand how the sum of the series grows as we incorporate more terms.
It provides insight into the overall structure of the series and allows us to later calculate the total sum for an infinite number of terms, should that be possible.
Limit of a Sequence
The concept of a limit is crucial in determining the sum of an infinite series. When analyzing a partial sum \( S_N \), we aim to find its limit as \( N \) approaches infinity.
This means we're interested in the value that \( S_N \) approaches when we include infinitely many terms in the series. By understanding this limit, we can conclude the behavior or sum of the entire series.
In the given problem, simplifying the expression \( \frac{N+1}{N+4} \) and evaluating \( \lim_{N \to \infty} \frac{N+1}{N+4} \), we arrive at 1. Thus, the limit of the partial sum is 1, indicating that the sum of the infinite series converges to this value.
Convergence of Series
To say that a series converges means that as you add more and more terms, the sum approaches a specific finite value. This convergence is determined by the limit of its partial sums.
If the limit exists and is finite, the series is convergent. Otherwise, it's either divergent or conditioned on additional criteria.
In our solution, the infinite series sum \( \sum_{n=1}^{\infty} a_n \) converges because the partial sums, \( S_N = \frac{N+1}{N+4} \), have a limit as \( N \to \infty \) that is finite. The limit is calculated to be 1. Therefore, the series converges to this number, meaning the total sum of the series doesn't grow endlessly but stabilizes at this value of 1.
Calculus
Calculus provides the foundational tools necessary to understand and work with infinite series. The concept of a limit, a fundamental idea in calculus, is what allows us to deal with series that involve infinitely many terms.
Using calculus, we analyze how functions behave as they approach certain points, which is instrumental in identifying the limits of sequences and partial sums.
In the exercise, we utilized calculus by applying the limit concept to the partial sum formula \( S_N = \frac{N+1}{N+4} \). By evaluating the limit of this expression as \( N \to \infty \), we conclude that the series converges to 1. Thus, calculus allows us to rigorously demonstrate that the infinite series settles at a summed value, bringing clarity to the behavior of the series over an infinite span.

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Most popular questions from this chapter

Use the Uniqueness Theorem to determine the coefficients \(\left\\{a_{n}\right\\}\) of the solution \(y(x)=\sum_{n=0}^{\infty} a_{n} x^{n}\) of the given initial value problem. \(d y / d x=2 y \quad y(0)=3\)

Let \(\left\\{a_{n}\right\\}\) be a sequence of positive numbers. In a course on mathematical analysis, one learns that if the two limits \(\lim _{n \rightarrow \infty} a_{n+1} / a_{n}\) and \(\lim _{n \rightarrow \infty} a_{n}^{1 / n}\) exist, then they are equal. In each of Exercises \(65-68\), produce a plot that illustrates the equality of these two limits. Your plot should include a horizontal line that is the asymptote of the points \(\left\\{\left(n, a_{n+1} / a_{n}\right)\right\\}\) and \(\left\\{\left(n, a_{n}^{1 / n}\right)\right\\}\). \(a_{n}=n ! / n^{n}\)

Consider the initial value problem $$ \frac{d y}{d x}=2-x-y, \quad y(0)=1 $$ \(\begin{array}{llll}\text { a. Calculate the power series } & \text { expansion }\end{array}\) \(y(x)=\sum_{n=0}^{\infty} a_{n} x^{n}\) of the solution up to the \(x^{7}\) term. b. Using the coefficients you have calculated, plot \(S_{3}(x)=\sum_{n=0}^{3} a_{n} x^{n}\) in the viewing rectangle \([-2,2] \times\) [-10,1.7] c. The exact solution to the initial value problem is \(y(x)=3-x-2 e^{-x},\) as can be determined using the methods of Section 7.7 (in Chapter 7 ). Add the plot of the exact solution to the viewing window. From the two plots, we see that the approximation is fairly accurate for \(-1 \leq x \leq 1\), but the accuracy decreases outside this subinterval. d. To see the improvement in accuracy that results from using more terms in a partial sum, replace the graph of \(S_{3}(x)\) with that of \(S_{7}(x)\)

Determine whether the series converges absolutely, converges conditionally, or diverges. The tests that have been developed in Section 5 are not the most appropriate for some of these series. You may use any test that has been discussed in this chapter. \(\sum_{n=1}^{\infty}(-1)^{n} \frac{n !}{3^{n}}\)

Use partial fractions to calculate the \(N^{\text {th }}\) partial sum \(S_{N}\) of the given series in closed form. Sum the series by finding \(\lim _{N \rightarrow \infty} S_{N}\). $$ \sum_{n=1}^{\infty} \frac{1}{(2 n+1)(2 n+3)} $$

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