/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Find the sum of the given series... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the sum of the given series. $$ \sum_{n=-1}^{\infty}(2 / 3)^{2 n+1} $$

Short Answer

Expert verified
The sum of the series is \( \frac{27}{10} \).

Step by step solution

01

Identify the Series Type

The given series is \( \sum_{n=-1}^{\infty}(2 / 3)^{2n+1} \). This can be re-written in the form \( \sum_{n=-1}^{\infty} r^{f(n)} \) where \( r = \frac{2}{3} \) and \( f(n) = 2n + 1 \). The first term is \( \left(\frac{2}{3}\right)^{2(-1) + 1} = \left(\frac{2}{3}\right)^{-1} \). This is a geometric series.
02

Calculate the First Term

To find the first term of the series when \( n = -1 \), substitute into the expression: \( (2/3)^{2(-1)+1} = (2/3)^{-1} = \frac{3}{2} \). This is the first term of the series \( (a) \).
03

Determine the Common Ratio

In a geometric series of the form \( ar^n \), the common ratio \( r \) is found within the powers. Here the series is constructed such that \( \left(\frac{2}{3}\right)^{2n+1} \). The ratio between successive terms will be \( \left(\frac{2}{3}\right)^2 = \frac{4}{9} \).
04

Use the Geometric Series Sum Formula

The infinite geometric series sum formula is \( S = \frac{a}{1 - r} \), where \( a \) is the first term and \( r \) is the common ratio. Substitute \( a = \frac{3}{2} \) and \( r = \frac{4}{9} \) into the formula: \[ S = \frac{\frac{3}{2}}{1 - \frac{4}{9}} = \frac{\frac{3}{2}}{\frac{5}{9}}. \]
05

Simplify the Expression

Simplify the expression by finding the division \( \frac{\frac{3}{2}}{\frac{5}{9}} \). This is equivalent to multiplying by the reciprocal: \( \frac{3}{2} \times \frac{9}{5} = \frac{27}{10} \). Thus, the sum of the series is \( \frac{27}{10} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Convergence
When we talk about series in mathematics, one of the key ideas is whether a series converges or not. Convergence means that as you add more terms of the series, the sum gets closer and closer to a specific value. Think of it like this: if you keep adding fractions of a pie indefinitely, does your total pie size approach a certain number of whole pies? If yes, the series is convergent.

In our example, we deal with a geometric series. A geometric series converges if the absolute value of the common ratio, denoted as \( r \), is less than 1. It's like filling a bucket with decreasing amounts of water: with each scoop getting smaller, you eventually stop overfilling the bucket. For the given series, we determined that the common ratio \( r = \frac{4}{9} \) which is indeed less than 1, confirming the series converges.

Understanding series convergence is crucial as it allows us to use specific formulas to find the sum of all the terms, leading us to a more profound comprehension of infinite series.
Infinite Series
In the world of mathematics, an infinite series is a sequence of numbers that you keep adding forever. Unlike a regular series with a clear stopping point, an infinite one goes on and on. This might seem a bit bizarre—how can you sum something unending? That's where convergence comes into play.

For our example, the series starts from \( n = -1 \) to infinity. It's important to notice the pattern here: every term is formed from the previous term by multiplying by the common ratio. This keeps going no matter how far along you go.
  • The first term is identified as \( \frac{3}{2} \).
  • Each subsequent term is a fraction of the previous because of the common ratio \( \frac{4}{9} \).

The idea is to grasp that even though you're adding an endless list of terms, the process has structure, making it meaningful to talk about a total sum. Thanks to convergence, each additional term contributes less and less to the total, allowing us to calculate a finite sum.
Geometric Series Sum Formula
The geometric series sum formula is a lifesaver when dealing with infinite series. It simplifies calculations by offering a direct way to find the sum if certain conditions are met. For a series to use this special formula, it must be geometric, and the common ratio's absolute value has to be less than 1.

The formula itself is \( S = \frac{a}{1 - r} \), where:
  • \( S \) represents the sum of the series.
  • \( a \) is the first term of the series.
  • \( r \) is the common ratio.

In our series, substituting these values-gives \( a = \frac{3}{2} \) and \( r = \frac{4}{9} \). Plug these into the formula: \[ S = \frac{\frac{3}{2}}{1 - \frac{4}{9}} = \frac{\frac{3}{2}}{\frac{5}{9}}. \]

Simplifying this gives a sum of \( \frac{27}{10} \), illustrating the power of this formula in finding solutions directly and efficiently, turning what might seem impossible into a straightforward calculation.

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Most popular questions from this chapter

Consider the initial value problem $$ \frac{d y}{d x}=x^{2}+y, \quad y(0)=1 $$ \(\begin{array}{llll}\text { a. Calculate } & \text { the power } & \text { series } & \text { expansion }\end{array}\) \(y(x)=\sum_{n=0}^{\infty} a_{n} x^{n}\) of the solution up to the \(x^{7}\) term. b. Using the coefficients you have calculated, plot \(S_{3}(x)=\sum_{n=0}^{3} a_{n} x^{n}\) in the viewing rectangle \([-3,3] \times\) [-11,44] c. The exact solution to the initial value problem is \(y(x)=3 e^{x}-x^{2}-2 x-2,\) as can be determined using the methods of Section 7.7 in Chapter 7 . Add the plot of the exact solution to the viewing window. From the two plots, we see that the approximation is fairly accurate for \(-1 \leq x \leq 1\), but the accuracy decreases outside this subinterval. d. When a partial sum \(S_{N}(x)\) is used to approximate an infinite series, an increase in the value of \(N\) requires more computation, but improved accuracy is the reward. To see the effect in this example, replace the graph of \(S_{3}(x)\) with that of \(S_{7}(x)\).

Let \(\left\\{a_{n}\right\\}\) be a sequence of positive numbers. In a course on mathematical analysis, one learns that if the two limits \(\lim _{n \rightarrow \infty} a_{n+1} / a_{n}\) and \(\lim _{n \rightarrow \infty} a_{n}^{1 / n}\) exist, then they are equal. In each of Exercises \(65-68\), produce a plot that illustrates the equality of these two limits. Your plot should include a horizontal line that is the asymptote of the points \(\left\\{\left(n, a_{n+1} / a_{n}\right)\right\\}\) and \(\left\\{\left(n, a_{n}^{1 / n}\right)\right\\}\). \(a_{n}=e^{n} / \ln (1+n)\)

The inequality $$ \frac{3 \sin (t)}{2+\cos (t)}0) $$ was discovered by Nicholas Cusa in \(1458 .\) Calculate the Taylor polynomial of degree 5 for \(f(t)=3 \sin (t) /(2+\cos (t))\) about \(c=0 .\) Use it to explain Cusa's inequality for small positive values of \(t\).

In each of Exercises 49-54, use Taylor series to calculate the given limit. $$ \lim _{x \rightarrow 0} \frac{\arctan (x)-x}{x^{3}} $$

In each of Exercises 82-85, use an alternating Maclaurin series to approximate the given expression to four decimal places. $$ \arctan (0.15) $$

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