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Use the Limit Comparison Test to determine whether the given series converges or diverges. $$ \sum_{n=1}^{\infty} \frac{(n-1)^{2}}{(n+1)^{4}} $$

Short Answer

Expert verified
The series converges.

Step by step solution

01

Identify the Series for Comparison

The given series is \( \sum_{n=1}^{\infty} \frac{(n-1)^{2}}{(n+1)^{4}} \). To apply the Limit Comparison Test, choose a simpler series for comparison, ideally a p-series. Here, we choose \( \sum_{n=1}^{\infty} \frac{1}{n^{2}} \), which is a known convergent p-series with \( p = 2 \).
02

Establish the Ratio of Corresponding Terms

Compute the ratio \( \frac{a_n}{b_n} \), where \( a_n = \frac{(n-1)^{2}}{(n+1)^{4}} \) and \( b_n = \frac{1}{n^{2}} \). The ratio is:\[\frac{a_n}{b_n} = \frac{(n-1)^{2}/(n+1)^{4}}{1/n^{2}} = \frac{(n-1)^{2} \cdot n^{2}}{(n+1)^{4}}\]
03

Simplify and Find the Limit

Simplify the expression:\[\frac{(n-1)^{2} \cdot n^{2}}{(n+1)^{4}} = \frac{n^{4} - 2n^{3} + n^{2}}{n^{4}+4n^{3}+6n^{2}+4n+1}\]Find the limit as \( n \to \infty \):\[L = \lim_{n \to \infty} \frac{n^{4} - 2n^{3} + n^{2}}{n^{4}+4n^{3}+6n^{2}+4n+1} = \lim_{n \to \infty} \frac{1 - \frac{2}{n} + \frac{1}{n^{2}}}{1 + \frac{4}{n} + \frac{6}{n^{2}} + \frac{4}{n^{3}} + \frac{1}{n^{4}}} = 1\]
04

Assess Convergence Using Limit Comparison Test

The Limit Comparison Test states that if \( L = \lim_{n \to \infty} \frac{a_n}{b_n} \) is a positive finite number, then both series \( \sum a_n \) and \( \sum b_n \) will either both converge or both diverge. Since \( L = 1 \) is a positive finite number and we know that \( \sum \frac{1}{n^{2}} \) converges, it follows that \( \sum \frac{(n-1)^{2}}{(n+1)^{4}} \) also converges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence and Divergence
In calculus, a series is essentially the sum of the terms of a sequence. One of the critical aspects of studying series is determining whether they converge or diverge. **Convergence** means that the series approaches a specific number as more and more terms are added. In contrast, **divergence** implies that the series does not settle to a particular value, often increasing indefinitely.

Understanding whether a series converges or diverges is crucial because it tells us about the behavior of the series as the number of terms goes to infinity. A common way to test for convergence or divergence is by using various tests like the Limit Comparison Test, which we will discuss later, or considering specific types of series such as the p-series. Recognizing the behavior of series helps in mathematical modeling, physics, engineering, and financial mathematics.
P-Series
A p-series is a specific type of series that takes the form \[\sum_{n=1}^{\infty} \frac{1}{n^{p}} \]where "p" is a constant. The convergence or divergence of a p-series depends primarily on the value of "p". Here's a simple rule to remember:
  • If \( p > 1 \), the series converges.
  • If \( p \leq 1 \), the series diverges.

The p-series is fundamental because it serves as a benchmark for comparing other series. For example, in the Limit Comparison Test used in our exercise, we compare the given series to a known convergent p-series \( \sum \frac{1}{n^2} \) where \( p = 2 \), indicating convergence. This kind of comparison offers a clearer insight into the behavior of more complex series.
Series Comparison
Series comparison is a powerful tool for understanding the behavior of infinite series. When faced with a complicated series, we often compare it to a simpler, well-known series to determine convergence or divergence. The Limit Comparison Test is a specific technique that helps in these situations.

The process involves calculating the limit of the ratio of the two series. If the limit of this ratio is a positive finite number, both series will have the same convergence behavior. It's similar to comparing two growth rates; if they grow at a similar pace, they should behave similarly as they extend to infinity.

Using the Limit Comparison Test in our example, we found that the ratio of the series \( \frac{a_n}{b_n} \) approached 1 as \( n \) went to infinity. Since we know \( \sum \frac{1}{n^2} \) converges, the original series must also converge. This technique provides a robust method for dealing with complex series.
Infinite Series
An infinite series is the sum of an infinite sequence of numbers. Unlike finite sums, which provide a straightforward total, infinite series require examination to understand their behavior. Infinite series appear in various domains such as calculus, analysis, and applied mathematics due to their use in approximations and problem-solving.

The "infinite" aspect means we are summing an unending number of terms, but this "sum" can actually converge to a specific number or diverge. Understanding whether an infinite series converges or diverges gives insight into the "sum" of infinitely many values.

The series in our exercise is an example of an infinite series. We used the Limit Comparison Test to determine its behavior, illustrating how such series are handled analytically. Grasping the concept of infinite series is essential for deeper mathematical understanding, particularly when dealing with functions and algorithms that rely on summing terms indefinitely.

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