/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Is the average value of \(\cos (... [FREE SOLUTION] | 91Ó°ÊÓ

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Is the average value of \(\cos (x)\) for \(0 \leq x \leq \pi / 4\) equal to the reciprocal of the average value of \(1 / \cos (x)\) over the same \(x\) -interval?

Short Answer

Expert verified
No, the averages are not reciprocals of each other.

Step by step solution

01

Determine the Average Value of \( \cos(x) \)

The average value of a function \( f(x) \) over an interval \([a, b]\) is given by the formula \( \frac{1}{b-a} \int_{a}^{b} f(x) \, dx \). For \( \cos(x) \) over the interval \( \left[0, \frac{\pi}{4}\right] \), this becomes \[ \frac{1}{\frac{\pi}{4} - 0} \int_{0}^{\frac{\pi}{4}} \cos(x) \, dx = \frac{4}{\pi} \int_{0}^{\frac{\pi}{4}} \cos(x) \, dx. \] The integral \( \int \cos(x) \, dx \) is \( \sin(x) + C \). Evaluating from 0 to \( \frac{\pi}{4} \), we get \[ \sin\left(\frac{\pi}{4}\right) - \sin(0) = \frac{\sqrt{2}}{2} - 0. \] Therefore, the average value of \( \cos(x) \) is \( \frac{4}{\pi} \times \frac{\sqrt{2}}{2} = \frac{2\sqrt{2}}{\pi}. \)
02

Determine the Average Value of \( \frac{1}{\cos(x)} \)

Using the same average value formula, the average value of \( \frac{1}{\cos(x)} \) is \[ \frac{4}{\pi} \int_{0}^{\frac{\pi}{4}} \frac{1}{\cos(x)} \, dx = \frac{4}{\pi} \int_{0}^{\frac{\pi}{4}} \sec(x) \, dx. \] The integral of \( \sec(x) \) is \( \ln|\sec(x) + \tan(x)| + C \). Evaluating from 0 to \( \frac{\pi}{4} \), the result is \[ \ln|\sec\left(\frac{\pi}{4}\right) + \tan\left(\frac{\pi}{4}\right)| - \ln|\sec(0) + \tan(0)| = \ln(\sqrt{2} + 1) - \ln(1) = \ln(\sqrt{2} + 1). \] Thus, the average value of \( \frac{1}{\cos(x)} \) is \( \frac{4}{\pi} \ln(\sqrt{2} + 1). \)
03

Compare the Average Values and Their Reciprocals

The average value of \( \cos(x) \) is \( \frac{2\sqrt{2}}{\pi} \) and the reciprocal of the average value of \( \frac{1}{\cos(x)} \) is \( \frac{\pi}{4 \ln(\sqrt{2} + 1)} \). We need to check if \( \frac{2\sqrt{2}}{\pi} = \frac{\pi}{4 \ln(\sqrt{2} + 1)} \). These expressions are clearly different as \( \frac{2\sqrt{2}}{\pi} \) depends on \( \sqrt{2} \) while the second depends on the logarithm of \( \sqrt{2} + 1 \). Therefore, these two average values and their reciprocal relationship are not equal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Integrals
Trigonometric integrals are integrals that involve trigonometric functions, such as sine, cosine, tangent, and their reciprocals. They play a crucial role in calculus, especially when working with periodic functions.
To solve a trigonometric integral, it often involves using known antiderivatives of trigonometric functions.
  • For example, the integral of \( \cos(x) \) is \( \sin(x) + C \), where \( C \) is the constant of integration.
  • Similarly, the integral of \( \sin(x) \) is \( -\cos(x) + C \).
To determine average values over specific intervals, such as \( 0 \leq x \leq \frac{\pi}{4} \), we use these antiderivatives.
These integrals help us calculate the area under the curve of trigonometric functions, which can further be used for finding average values over a given domain.
Mastering these integrals requires familiarity with both the trigonometric functions themselves and the fundamental theorem of calculus.
Integration Techniques
Integration techniques are methods used to evaluate integrals that are not immediately solvable with basic antiderivative rules. In the context of trigonometric functions, these techniques often include:
  • Integration by substitution: This involves changing the variable of integration to simplify the expression, which can make the integration process easier.
  • Integration by parts: This technique is beneficial when dealing with products of functions, and it uses the product rule in reverse.
  • Trigonometric identities: These identities allow us to rewrite integrands in a more integrable form.
For instance, to integrate \( \frac{1}{\cos(x)} \) or \( \sec(x) \), we use the formula for its integral: \( \ln|\sec(x) + \tan(x)| + C \). Understanding and applying these techniques are essential for solving complex integrals accurately.
Trigonometric Identities
Trigonometric identities are equations that hold true for all values of the variable involved, and they are essential tools in simplifying integrals. They provide relationships between trigonometric functions that can simplify calculus problems significantly.
Some fundamental trigonometric identities include:
  • Pythagorean identity: \( \sin^2(x) + \cos^2(x) = 1 \)
  • Reciprocal identities: such as \( \sec(x) = \frac{1}{\cos(x)} \)
  • Angle sum and difference identities: which express the sine or cosine of sums or differences of angles in terms of their individual angles.
In the original exercise, understanding the reciprocal identity, \( \sec(x) = \frac{1}{\cos(x)} \), was crucial when comparing the average values of \( \cos(x) \) and \( \frac{1}{\cos(x)} \).
By using identities to simplify expressions, particularly integrands, one can more easily find an integral or reduce complex expressions into simpler, more manageable forms.

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