Chapter 5: Problem 36
In each of Exercises \(27-38\), calculate the right endpoint approximation of the area of the region that lies below the graph of the given function \(f\) and above the given interval \(I\) of the \(x\) -axis. Use the uniform partition of given order \(N\). $$ f(x)=\sec (x) \quad I=[-\pi / 3, \pi / 3], N=4 $$
Short Answer
Step by step solution
Determine Partition Width
Identify Right Endpoints
Evaluate the Function at Right Endpoints
Calculate the Right Endpoint Approximation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partition Width
- Total interval length: \( \frac{2\pi}{3} \)
- Partition width: \( \Delta x = \frac{2\pi/3}{4} = \frac{\pi}{6} \)
Right Endpoints
- Starting at \(-\frac{\pi}{3}\), increment by \( \frac{\pi}{6} \) to find each endpoint:
- \( x_1 = -\frac{\pi}{3} + \frac{\pi}{6} = -\frac{\pi}{6} \)
- \( x_2 = 0 \)
- \( x_3 = \frac{\pi}{6} \)
- \( x_4 = \frac{\pi}{3} \)
Secant Function
When evaluating the secant function at the right endpoints:
- \( f(-\frac{\pi}{6}) = \sec(-\frac{\pi}{6}) = \frac{2}{\sqrt{3}} \)
- \( f(0) = \sec(0) = 1 \)
- \( f(\frac{\pi}{6}) = \frac{2}{\sqrt{3}} \)
- \( f(\frac{\pi}{3}) = 2 \)
Subinterval
- In our example, the interval \( I = \left[ -\frac{\pi}{3}, \frac{\pi}{3} \right] \) is divided into \( N = 4 \) subintervals.
- Each subinterval has a width \( \Delta x = \frac{\pi}{6} \).