Chapter 5: Problem 10
A function \(f\) is defined on a specified interval \(I=[a, b] .\) Calculate the area of the region that lies between the vertical lines \(x=a\) and \(x=b\) and between the graph of \(f\) and the \(x\) -axis. $$ f(x)=\left(x^{2}-1\right)(x-2) \quad I=[-2,2] $$
Short Answer
Expert verified
The area between the curve and the x-axis on \([-2, 2]\) is 0.
Step by step solution
01
Determine the Integral Setup
To find the area between the curve and the x-axis from \(x = a\) to \(x = b\), we need to evaluate the definite integral \( \int_{a}^{b} f(x) \, dx \). For the given function \( f(x) = (x^2 - 1)(x - 2) \), the integral becomes \( \int_{-2}^{2} (x^2 - 1)(x - 2) \, dx \).
02
Expand the Function
Expand the function \( f(x) = (x^2 - 1)(x - 2) \). First, multiply \(x^2 - 1\) by \(x\) to get \(x^3 - x\), then multiply \(-2\) with \(x^2 - 1\) to get \(-2x^2 + 2\). Combine them to get \( f(x) = x^3 - x - 2x^2 + 2 = x^3 - 2x^2 - x + 2 \).
03
Integrate the Function
Integrate \( f(x) = x^3 - 2x^2 - x + 2 \) from \(-2\) to \(2\). The integral is: \[ \int_{-2}^{2} (x^3 - 2x^2 - x + 2) \, dx = \left[ \frac{x^4}{4} - \frac{2x^3}{3} - \frac{x^2}{2} + 2x \right]_{-2}^{2} \].
04
Evaluate the Definite Integral
Substitute the limits \(-2\) and \(2\) into the integrated function:1. Evaluate at \(x = 2\): \(\frac{2^4}{4} - \frac{2 \times 2^3}{3} - \frac{2^2}{2} + 2 \times 2 = 4 - \frac{16}{3} - 2 + 4 = \frac{10}{3}\).2. Evaluate at \(x = -2\): \(\frac{(-2)^4}{4} - \frac{2 \times (-2)^3}{3} - \frac{(-2)^2}{2} + 2 \times (-2) = 4 + \frac{16}{3} - 2 - 4 = \frac{10}{3}\).3. Calculate the difference: \( \frac{10}{3} - \frac{10}{3} = 0 \).
05
Interpret the Result
The result of the integral calculation, which is \(0\), implies that the area above the x-axis is completely balanced by the area below the x-axis within the given interval \([-2, 2]\). Therefore, the net area is zero.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Calculating Area
When we talk about calculating the area under a curve, we're essentially trying to find out the size of the "space" that the function covers between two points on the x-axis. Imagine drawing a shape on graph paper and counting how many squares it covers. The concept of area under a curve is similar, but it's like trying to measure the space in a more fluid, continuous way.
To achieve this, we use calculus, specifically integration. In mathematical terms, the area under a curve from a point \(a\) to a point \(b\) is found using the definite integral of the function. Here's a simplified breakdown:
To achieve this, we use calculus, specifically integration. In mathematical terms, the area under a curve from a point \(a\) to a point \(b\) is found using the definite integral of the function. Here's a simplified breakdown:
- First, identify the interval \([a, b]\) over which you want to measure the area.
- Set up an integral with these limits; \( \int_{a}^{b} f(x) \, dx \).
- Evaluate this integral to find the area.
Polynomial Functions
Polynomial functions are mathematical expressions consisting of variables raised to whole number exponents, and they look like a sequence of terms added or subtracted together. For example, \( f(x) = (x^2 - 1)(x - 2) \) is a polynomial function.
Understanding polynomials involves looking at their structure:
Understanding polynomials involves looking at their structure:
- Terms: Individual parts of a polynomial, like \(x^2\) or \(-1\).
- Coefficients: Numbers multiplying the variable, such as \(-2\) in \(-2x\).
- Degree: The highest power the variable is raised to; here it is 3, because of \(x^3\).
Definite Integral Calculation
Definite integral calculation is a core concept in calculus used to quantify the area under a curve between two points. In our specific example, the process went as follows:
First, we identified our function as \(f(x) = x^3 - 2x^2 - x + 2\) and needed to calculate the integral over \([-2, 2]\). The steps to evaluate a definite integral include:
First, we identified our function as \(f(x) = x^3 - 2x^2 - x + 2\) and needed to calculate the integral over \([-2, 2]\). The steps to evaluate a definite integral include:
- Integrate: Find the antiderivative. For each term, this involves slightly increasing the exponent and dividing by the new exponent, transforming expressions like \(x^3\) into \(\frac{x^4}{4}\).
- Evaluate Boundaries: Substitute the upper and lower limits into the antiderivative and find the difference.
- Finding the Area: Calculate the result by subtracting the lower limit evaluation from the upper limit.