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Suppose that \(\int_{1}^{3} f(x) d x=-8\) and \(\int_{3}^{7} f(x) d x=12\). Evaluate \(\int_{1}^{7} f(x) d x\)

Short Answer

Expert verified
The value of \(\int_{1}^{7} f(x) dx\) is 4.

Step by step solution

01

Understand the problem

We are given two definite integrals: \(\int_{1}^{3} f(x) dx = -8\) and \(\int_{3}^{7} f(x) dx = 12\). The task is to find the value of \(\int_{1}^{7} f(x) dx\) using these given integrals.
02

Apply the property of integrals

Recognize that the integral from 1 to 7 can be split into two separate integrals. Using the property of integrals, \(\int_{1}^{7} f(x) dx = \int_{1}^{3} f(x) dx + \int_{3}^{7} f(x) dx\). This allows us to utilize the given values directly.
03

Substitute known values

Substitute the known values of the integrals given in the problem into the expression from Step 2. We have \(\int_{1}^{3} f(x) dx = -8\) and \(\int_{3}^{7} f(x) dx = 12\). Thus, \(\int_{1}^{7} f(x) dx = -8 + 12\).
04

Calculate the result

Perform the arithmetic operation: \(-8 + 12 = 4\). Thus, the integral \(\int_{1}^{7} f(x) dx = 4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integral Properties
Understanding integral properties is crucial when tackling calculus problems, especially those involving definite integrals. One key property to know is the **additive property of integrals**, which allows us to combine integrals over adjacent intervals into one overarching integral. For instance, if you have two integrals
  • defined over the ranges from 1 to 3 and from 3 to 7, they can be combined.
  • This gives us the integral from 1 to 7, as shown by: \[ \int_{1}^{7} f(x) \, dx = \int_{1}^{3} f(x) \, dx + \int_{3}^{7} f(x) \, dx \]
This property is invaluable in simplifying problems because it allows direct integration of known values over contiguous segments.
By understanding this property, you can seamlessly piece together separate integrals to solve more complex calculus problems.
Calculus Problem Solving
Solving calculus problems, particularly those involving integrals, requires a strategic approach. Here's a simplified approach to addressing them:
  • First, **understand the problem and the values involved**. Take note of initial conditions, such as the given integral values in the problem: \( \int_{1}^{3} f(x) \, dx = -8 \) and \( \int_{3}^{7} f(x) \, dx = 12 \).
  • Next, **employ key calculus properties**. As discussed, use the additive nature of integrals to combine known information: \[\int_{1}^{7} f(x) \, dx = \int_{1}^{3} f(x) \, dx + \int_{3}^{7} f(x) \, dx\]
  • Finally, **substitute the known values** and perform the necessary arithmetic operations. By substituting \(-8\) and \(12\) for the integrals, you can simplify:\[-8 + 12 = 4\]
With these steps, complex integrals become easier to manage. This methodical approach aids tremendously in reducing errors and ensures that you're leveraging all available information effectively.
Arithmetic Operations in Calculus
Arithmetic operations are a fundamental component in solving calculus problems, particularly those involving the evaluation of integrals. Once you've expressed the problem using integral properties, the arithmetic operations come into play.
  • These operations allow you to simplify and solve expressions that arise from combining integrals.
  • Take, for example, the operation involved in combining the integrals’ values: \(-8 + 12\).
Performing this arithmetic leads you to the result of the integral from 1 to 7. Although it might seem straightforward, proper execution of these operations is crucial. Even a simple misstep in arithmetic can lead to incorrect results, masking your understanding of integral properties and calculus problem-solving strategies.
Using the approach highlighted earlier ensures accuracy in both understanding and execution, making calculus problems more accessible.

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Most popular questions from this chapter

A function \(f\) and an interval \([a, b]\) are specified. Calculate the Simpson's Rule approximations of \(\int_{a}^{b} f(x) d x\) with \(N=10\) and \(N=20 .\) If the first five decimal places do not agree, increment \(N\) by \(10 .\) Continue until the first five decimal places of two consecutive approximations are the same. State your answer rounded to four decimal places. $$ f(x)=\ln \left(1+x^{2}\right) $$

An integral \(\int_{a}^{b} f(x) d x\) and a positive integer \(N\) are given. Compute the exact value of the integral, the Simpson's Rule approximation of order \(N,\) and the absolute error \(\varepsilon\). Then find a value \(c\) in the interval \((a, b)\) such that \(\varepsilon=(b-a)^{5}\left|f^{(4)}(c)\right| /\left(180 \cdot N^{4}\right) .\) (This form of the error, which resembles the Mean Value Theorem, implies inequality \((5.8 .4) .)\) $$ \int_{1}^{e} 1 / x d x \quad N=4 $$

Income data for three countries are given in the following tables. In each table, \(x\) represents a percentage, and \(L(x)\) is the corresponding value of the Lorenz function, as described in Example \(3 .\) In each of Exercises \(23-27,\) use the specified approximation method to estimate the coefficient of inequality for the indicated country. (The values \(L(0)=0\) and \(L(100)=100\) are not included in the tables, but they should be used.) $$ \begin{array}{|c|r|c|c|c|}\hline x & 20 & 40 & 60 & 80 \\\\\hline L(x) & 5 & 20 & 30 & 55\\\\\hline\end{array}$$ Income Data, Country A $$\begin{array}{|c|c|c|c|}\hline x & 25 & 50 & 75 \\\\\hline L(x) & 15 & 25 & 40 \\\\\hline\end{array}$$ Income Data, Country B $$\begin{array}{|c|r|r|r|r|r|r|r|r|r|}\hline \boldsymbol{x} & 10 & 20 & 30 & 40 & 50 & 60 & 70 & 80 & 90 \\\\\hline \boldsymbol{L}(\boldsymbol{x}) & 4 & 8 & 14 & 22 & 32 & 42 & 56 & 70 & 82 \\\\\hline\end{array}$$ Income Data, Country \(\mathbf{C}\) Country C Simpson's Rule

A function \(f,\) an interval \(I,\) and an even integer \(N\) are given. Approximate the integral of \(f\) over \(I\) by partitioning \(I\) into \(N\) equal length subintervals and using the Midpoint Rule, the Trapezoidal Rule, and then Simpson's Rule. $$ f(x)=15 x /(1+x) \quad I=[0,4], N=4 $$

Find the area of the region that is bounded by the graphs of \(y=f(x)\) and \(y=g(x)\) for \(x\) between the abscissas of the two points of intersection. $$ f(x)=x^{2}-1 \quad g(x)=8 $$

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