Chapter 4: Problem 17
Calculate the indefinite integral. $$ \int \sec ^{2}(8 x) d x $$
Short Answer
Expert verified
The indefinite integral of \(\int \sec^2(8x) \, dx\) is \(\frac{1}{8} \tan(8x) + C\).
Step by step solution
01
Identify the Integral Formula
The integral \(\int \sec^2(kx)\, dx\)reminds us of the standard integral formula \(\int \sec^2(u)\, du = \tan(u) + C\). We know that the derivative of the tangent function is the secant squared function, i.e., \(\frac{d}{dx}[\tan(x)] = \sec^2(x)\).
02
Use Substitution Method
To use the formula for integration, we'll perform a substitution. Let \(u = 8x\). Then, differentiate \(u\) with respect to \(x\) to find \(du\).
03
Differentiate the Substitution Variable
Differentiating \(u = 8x\) with respect to \(x\), we get \(\frac{du}{dx} = 8\). This implies that \(dx = \frac{du}{8}\).
04
Change Variables in the Integral
Substitute \(u\) and solve the integral: \(\int \sec^2(8x) \, dx = \int \sec^2(u) \frac{du}{8}\). Factor out the 1/8 outside the integral, resulting in \(\frac{1}{8} \int \sec^2(u) \, du\).
05
Solve the Integral
Using the formula \(\int \sec^2(u)\, du = \tan(u) + C\), we get: \(\frac{1}{8} \tan(u) + C\).
06
Substitute Back the Original Variable
Return to the original variable by substituting back \(u = 8x\) into \(\tan(u)\). The resulting expression is \(\frac{1}{8} \tan(8x) + C\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
integration by substitution
Integration by substitution is a powerful tool that helps simplify complex integrals, making them easier to solve. Imagine substitution as a method of translating the integral into a more familiar form. In the original exercise, the expression was \[ \int \sec ^2(8x) \, dx \]. By using substitution, we change variables to make integration straightforward. We choose \( u = 8x \) for our substitution, so the differential du can be found by differentiatingu with respect to x , giving us \( du/dx = 8 \) or \( du = 8 \, dx \).
- We swapped the variable \(8x\) with \(u\) to simplify the structure.
- This alteration transformed the integral into \( \int \sec ^2(u) \frac{du}{8} \), which is easier to evaluate.
secant function
The secant function is an essential trigonometric function often encountered in calculus. It is the reciprocal of the cosine function: \( \sec(x) = \frac{1}{\cos(x)} \). The integral given in the problem, \( \int \, \sec^2(8x) \, dx \), focuses on the square of the secant function.Knowing the relationship between secant and cosine is useful. The derivative of the tangent function we use during integration reveals why \( \sec^2(x) \) shows up in differentiation and integration processes:
- The derivative of \( \tan(x) \) is exactly \( \sec^2(x) \).
- This is why spotting an integral of \( \, \sec^2(x) \frac{du}{dx} \, \) pointers us towards using the **tangent** function in our solution.
differentiation
Differentiation is the process of finding a derivative, which marks the rate of change of a function with respect to variables. In the context of our substitution method, differentiation becomes crucial. When we let \( u = 8x \) and aimed to replace \( dx \), differentiating \( u \) led to \( du = 8 \, dx \).Here, differentiating serves two main purposes:
- It finds the differential formula necessary for completing a substitution.
- It verifies whether a function’s derivative aligns with the function we integrate, such as \( \tan(u) \), which has \( \sec^2(u) \) as its derivative.
integration techniques
In calculus, integration techniques are various strategies used to tackle different integrals. Each technique serves a specific role and contributes uniquely to solving problems. Let's dive into a couple of them that are relevant to our problem:**Substitution Method**
- This method is often used when the integral includes a composition of functions. Like in our original exercise, where the integral involved \(\sec^2(u)\), substitution simplified and made integration feasible.
- It's akin to undoing the chain rule, one of differentiation’s primary tactics.
- Trigonometric functions frequently appear in integration tasks. Recognizing common patterns, such as \(\sec^2(x)\) being derivative of \(\tan(x)\), equips us with accelerating solving techniques.