Chapter 4: Problem 12
Use the first derivative to determine the intervals on which the given function \(f\) is increasing and on which \(f\) is decreasing. At each point \(c\) with \(f^{\prime}(c)=0,\) use the First Derivative Test to determine whether \(f(c)\) is a local maximum value, a local minimum value, or neither. $$ f(x)=(x+1)^{2}(x+2)^{2} $$
Short Answer
Step by step solution
Find the First Derivative
Find Critical Points
Determine Test Intervals
Apply the First Derivative Test
Determine Local Maxima and Minima
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First Derivative Test
After finding the derivative, divide your x-axis into intervals based on these critical points. Choose a test point from each interval and substitute it into the derivative to determine if the function is increasing or decreasing. The First Derivative Test tells you whether a critical point is a local maximum, local minimum, or neither by observing the sign changes of the derivative around that point. If the derivative changes from positive to negative, it’s a local maximum. From negative to positive, it’s a local minimum.
Critical points
- Find the first derivative of the function. This is key to determining the rate of change of the function at any x point.
- Set the derivative equal to zero and solve for x. Also, check where the derivative is undefined.
- In our exercise, solving the equation \( 4(x+1)(x+2)(2x+3) = 0 \) gives us the critical points: \( x = -1, -2, -\frac{3}{2} \).
Intervals of increase and decrease
- Create intervals on the x-axis. Use critical points to break the number line into different sections.
- Select a test point from each interval. For example, use \( x = -3 \) for the interval \((-cinfty, -2)\), and check the sign of the derivative at that point.
- If the derivative at the test point is positive, the function is increasing in that interval. If negative, the function is decreasing.
Local maxima and minima
- Use the sign changes of the derivative around critical points. This will help identify the nature of these points.
- If the derivative changes from positive to negative at a critical point, it's a local maximum. If it changes from negative to positive, it's a local minimum.
- In our example, \(x = -2\) and \(x = -1\) are local minima because the function changes from decreasing to increasing, and \(x = -\frac{3}{2}\) is a local maximum as it changes from increasing to decreasing.