Chapter 3: Problem 55
Let $$f(x)=\left\\{\begin{array}{ll} x^{3} & \text { if } x>0 \\\\-x^{3} & \text { if } x \leq 0 .\end{array}\right.$$ a. Prove that \(f^{\prime}(0)\) exists and equals 0 . b. Prove that \(f^{\prime \prime}(0)\) exists and equals 0 . c. Prove that \(f^{\prime \prime \prime}(0)\) does not exist.
Short Answer
Expert verified
\(f'(0) = 0\), \(f''(0) = 0\), \(f'''(0)\) does not exist.
Step by step solution
01
Define Derivative at a Point
To prove that the derivative \(f'(0)\) exists, compute the limit \(\lim_{{h \to 0}} \frac{{f(h) - f(0)}}{h}\). Since \(f(0) = -0^3 = 0\), for the derivative at \(x = 0\), the expression simplifies to \(\lim_{{h \to 0}} \frac{{f(h)}}{h}\).
02
Evaluate Directional Limits for First Derivative
For \(h > 0\), \(f(h) = h^3\), so \(\frac{{f(h)}}{h} = \frac{{h^3}}{h} = h^2\). As \(h\) approaches 0 from the positive side, \(h^2\) approaches 0. For \(h < 0\), \(f(h) = -h^3\), so \(\frac{{f(h)}}{h} = \frac{{-h^3}}{h} = -h^2\). As \(h\) approaches 0 from the negative side, \(-h^2\) approaches 0. Both directional limits are 0.
03
Conclude Existence and Value of First Derivative
Since the directional limits \(\lim_{{h \to 0^+}} \frac{{f(h)}}{h} = 0\) and \(\lim_{{h \to 0^-}} \frac{{f(h)}}{h} = 0\) are equal, \(f'(0)\) exists and equals 0.
04
Define Second Derivative at a Point
To find \(f''(0)\), use the definition of the second derivative: \(f''(0) = \lim_{{h \to 0}} \frac{{f'(h) - f'(0)}}{h}\). Since \(f'(0) = 0\), simplify to \(\lim_{{h \to 0}} \frac{{f'(h)}}{h}\).
05
Compute First Derivative for \(x \neq 0\)
For \(x > 0\), the derivative \(f'(x) = 3x^2\). For \(x < 0\), \(f'(x) = -3x^2\).
06
Evaluate Directional Limits for Second Derivative
For \(h > 0\), \(f'(h) = 3h^2\), so \(\frac{{f'(h)}}{h} = \frac{{3h^2}}{h} = 3h\). As \(h\) approaches 0 from the positive side, \(3h\) approaches 0. For \(h < 0\), \(f'(h) = -3h^2\), so \(\frac{{f'(h)}}{h} = \frac{{-3h^2}}{h} = -3h\). As \(h\) approaches 0 from the negative side, \(-3h\) approaches 0.
07
Conclude Existence and Value of Second Derivative
Since the directional limits \(\lim_{{h \to 0^+}} \frac{{f'(h)}}{h} = 0\) and \(\lim_{{h \to 0^-}} \frac{{f'(h)}}{h} = 0\) are equal, \(f''(0)\) exists and equals 0.
08
Define Third Derivative at a Point
To show \(f'''(0)\) does not exist, compute \(f''(h)\) for \(heq 0\) and examine \(\lim_{{h \to 0}} \frac{{f''(h) - f''(0)}}{h}\). Since \(f''(0) = 0\), focus on \(\lim_{{h \to 0}} \frac{{f''(h)}}{h}\).
09
Compute Second Derivative for \(x \neq 0\)
For \(x > 0\), \(f''(x) = 6x\), and for \(x < 0\), \(f''(x) = -6x\).
10
Evaluate Limits for Third Derivative
For \(h > 0\), \(f''(h) = 6h\), so \(\frac{{f''(h)}}{h} = \frac{{6h}}{h} = 6\). For \(h < 0\), \(f''(h) = -6h\), so \(\frac{{f''(h)}}{h} = \frac{{-6h}}{h} = -6\). The directional limits \(\lim_{{h \to 0^+}} 6 = 6\) and \(\lim_{{h \to 0^-}} -6 = -6\) are not equal.
11
Conclude Non-existence of Third Derivative
Since the directional limits are not equal, \(f'''(0)\) does not exist.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Piecewise Functions
A piecewise function is a function that is defined by different expressions depending on the value of the independent variable. In this case, the function \[f(x) = \begin{cases} x^{3} & \text { if } x>0 \-x^{3} & \text { if } x \leq 0 \end{cases}\] is defined in two pieces:
- For values of \(x\) greater than 0, the function is defined as \(x^3\).
- For values of \(x\) that are less than or equal to 0, it is defined as \(-x^3\).
Limits and Continuity
In calculus, understanding limits is crucial for discussing the continuity and differentiability of a function. A limit is the value that a function (or sequence) "approaches" as the input (or index) approaches some value. When we say \[\lim_{h \to 0} \frac{f(h)}{h}\]we're evaluating how the expression behaves as \(h\) gets infinitely close to 0.
For the given piecewise function, its limit behavior helps determine continuity at points of interest:
For the given piecewise function, its limit behavior helps determine continuity at points of interest:
- Check the limit from both the positive and negative sides.
- For continuity to hold, the limits from both sides must be equal.
Higher-Order Derivatives
Moving beyond first and second derivatives, higher-order derivatives provide insight into how a function's curvature and rate of change develop. The task of assessing higher-order derivatives begins with fully understanding the behavior of the lower order derivatives. For the function,\[ f''(0) = 0 \] existed, indicating that the rate of change of the slope at \(x = 0\) was still constant.
However, further exploration into \[f'''(0)\]revealed contradictions:
However, further exploration into \[f'''(0)\]revealed contradictions:
- The third derivative tries to narrate the function's jerk, or the rate of change of acceleration.
- For \(x > 0\), the function seems to pull away in one direction, whereas for \(x < 0\), it does the opposite.