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91Ó°ÊÓ

Let \(f(x)=(3 x-\sin (2 x)) / x\) for \(-2 \leq x \leq 4, x \neq 0 .\) Locate the extreme values of \(f\) to four decimal places.

Short Answer

Expert verified
Find critical points by solving \(2x\cos(2x) = \sin(2x)\). Evaluate at endpoints for extreme values.

Step by step solution

01

Determine the Derivative

First, we need to find the derivative of the function \( f(x) = \frac{3x - \sin(2x)}{x} \). To make this easier, rewrite the function as \( f(x) = 3 - \frac{\sin(2x)}{x} \). The derivative is found using the quotient rule and the chain rule. After applying these rules, we find that:\( f'(x) = -\frac{d}{dx}\left(\frac{\sin(2x)}{x}\right) = \frac{2x \cos(2x) - \sin(2x)}{x^2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
The concept of a derivative is fundamental in calculus as it represents the rate of change of a function with respect to its variable. Essentially, the derivative tells us how a function changes at any given point. For the function \( f(x) \), its derivative \( f'(x) \) is a new function that gives the slope of the tangent line to the graph of \( f(x) \) at any point \( x \).

Here are some key points to remember about derivatives:
  • They are used to find the instantaneous rate of change, such as velocity or acceleration.
  • In a graphical sense, they represent the slope of the tangent line to the function at a particular point.
  • A critical application of derivatives is in finding the extreme values (maximums and minimums) of functions.
In the given exercise, the derivative \( f'(x) = \frac{2x \cos(2x) - \sin(2x)}{x^2} \) was found. We used this to locate the extreme values of the function, which are points where the function reaches its highest or lowest values within a given range.
Quotient Rule
The Quotient Rule is a technique used in calculus to find the derivative of a function that is the division of two other functions. When we have a function in the form \( \frac{u(x)}{v(x)} \), where both \( u(x) \) and \( v(x) \) are differentiable functions, the derivative can be found using the Quotient Rule.

The Quotient Rule states:\[\left( \frac{u}{v} \right)' = \frac{v \cdot u' - u \cdot v'}{v^2}\]where \( u' \) and \( v' \) are the derivatives of \( u \) and \( v \), respectively.

In the exercise, we applied the Quotient Rule to the component \( \frac{\sin(2x)}{x} \) as part of the process to find the derivative of \( f(x) = 3 - \frac{\sin(2x)}{x} \). This rule is essential when dealing with functions divided by one another, ensuring we correctly differentiate them so that we can analyze their behavior thoroughly.
Chain Rule
The Chain Rule is another pivotal concept in calculus that allows us to differentiate composite functions. A composite function is one where the output of one function is used as the input of another, symbolically expressed as \( h(x) = g(f(x)) \).

The Chain Rule states:\[h'(x) = g'(f(x)) \cdot f'(x)\]In simpler terms, the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.

In the context of our problem, the Chain Rule was applied when taking the derivative of \( \sin(2x) \). The derivative of \( \sin(2x) \) is \( 2\cos(2x) \) because of the presence of the inner function \( 2x \), with its derivative being \( 2 \).

Understanding and applying the Chain Rule is crucial when dealing with nested functions, ensuring we accurately determine how these functions change.

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Most popular questions from this chapter

When a drug is intravenously introduced into a patient's bloodstream at a constant rate, the concentration \(C\) of the drug in the patient's body is typically given by $$ C(t)=\frac{\alpha}{\beta}\left(1-e^{-\beta t}\right) $$ where \(\alpha\) and \(\beta\) are positive constants. What is the limiting concentration \(\lim _{t \rightarrow \infty} C(t) ?\) Sketch the graph of \(C .\) What horizontal asymptote does it have?

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In Exercises \(57-66\), use the basic limits of Theorem 8 to evaluate the limit. Note: \(x\) "means " \(x\) degrees." $$ \lim _{x \rightarrow 0} \frac{\sin ^{2}(x)}{1-\cos (x)} $$

If an amount \(A\) is to be received at time \(T\) in the future, then the present value of that payment is the amount \(P_{0}\) that, if deposited immediately with the current interest rate locked in, will grow to \(A\) by time \(T\) under continuous compounding. The present value of an income stream is the sum of the present values of each future payment. In each of Exercise \(82-85,\) calculate the present value of the specified income stream. Mr. Woodman pledges three equal payments of \(\$ 1000\) at yearly intervals to a forrest conservation organization. If the first installment is to be paid in two years, and if the current interest rate is \(4 \%,\) what is the present value of the donation?

In each of Exercises \(93-96,\) plot the given functions \(g, f,\) and \(h\) in a common viewing rectangle that illustrates \(f\) being pinched at the point \(c\). Determine \(\lim _{x \rightarrow c} f(x)\). $$ \begin{array}{l} g(x)=2-4|x|, f(x)=\left(2+x^{2}\right) /\left(1+x^{2}\right)+\sin (x+1 / x)+ \\ \sin (x-1 / x), h(x)=2(1+|x|) \quad c=0 \end{array} $$

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