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Suppose that \(a_{n} \rightarrow \ell \neq 0\). Show that \(\lim _{n \rightarrow \infty}\left(a_{n} / a_{n+1}\right)\) converges.

Short Answer

Expert verified
The limit \(\lim_{n \to \infty} \frac{a_n}{a_{n+1}}\) converges to 1.

Step by step solution

01

Understand the Limits

We are given that the sequence \(a_n\) converges to \(\ell\) with \(\ell eq 0\). We need to find if \(\lim_{n \rightarrow \infty} \frac{a_n}{a_{n+1}}\) converges.
02

Apply the Limit Laws

Since \(a_n \rightarrow \ell\), by limit properties, \(a_{n+1}\) also converges to \(\ell\). Using this, we can express the limit we need as \(\lim_{n \to \infty} \frac{a_n}{a_{n+1}} = \lim_{n \to \infty} \frac{a_n}{\ell} \cdot \frac{\ell}{a_{n+1}}\). Since both sequences \(a_n\) and \(a_{n+1}\) converge to \(\ell\), the expression simplifies to \(\lim_{n \rightarrow \infty} \frac{a_n}{a_{n+1}} = \frac{\ell}{\ell} = 1\).
03

Verify Convergence

From Step 2, we see that as \(a_n\) and \(a_{n+1}\) both approach \(\ell\), the ratio \(\frac{a_n}{a_{n+1}}\) approaches \(1\). Therefore, it follows that \(\lim_{n \to \infty} \frac{a_n}{a_{n+1}} = 1\), which demonstrates that this limit converges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Limits
In mathematics, a limit helps us understand the behavior of a sequence or function as it progresses towards a particular point. Imagine you have a sequence of numbers, like steps leading toward a finish line. As you take step after step, you get closer and closer to the finish line. This is what convergence means—getting nearer to a specific value as a sequence progresses.

In the provided exercise, the sequence \(a_n\) converges to a value \(\ell\), which is not zero. This means as the index, \(n\), becomes very large, the sequence \(a_n\) gets close to \(&\ell\). Similarly, \(a_{n+1}\), which is just the next element in the sequence, also converges to the same value \(\ell\).

Understanding how limits work involves applying specific rules, like the laws of limits, which let us manipulate sequences to find where they converge. In this case, knowing both \(a_n\) and \(a_{n+1}\) lead to \(\ell\) helps us analyze the ratio of their terms. This foundation lets us determine what the ratio converges to, ultimately verifying that our mathematical process is consistent and logical.
Applying the Ratio Test
The ratio test is a valuable tool in analyzing infinite series and is often implemented to understand the convergence or divergence of a sequence. Think of it as a technique that checks how successive terms in a sequence behave when compared to one another.

In the context of our exercise, we're looking at the ratio between consecutive terms: \(\lim_{n \to \infty} \frac{a_n}{a_{n+1}}\). Since both terms \(a_n\) and \(a_{n+1}\) converge to \(\ell\), we use the property that the limit of a quotient is the quotient of the limits (if the limits exist and are not zero).

Hence, this simplifies to be the limit of \(\frac{a_n}{\ell} \cdot \frac{\ell}{a_{n+1}}\), where both sequences go to \(\ell\). So, it becomes \(\frac{\ell}{\ell}\) which equals one. This result confirms that the sequence of ratios converges, providing a neat solution to the problem at hand.
Appreciating Mathematical Proof
A mathematical proof is a logical argument that establishes the truth of a given statement. Proofs are fundamental in ensuring mathematical concepts and conclusions are correct and reliable.

In proving that the limit \(\lim_{n \to \infty} \frac{a_n}{a_{n+1}}\) converges, we essentially want to show, through a series of logical steps, that the result holds under the initial conditions set by the problem.

When developing a proof for convergence, such as in our problem, you rely on previously established theorems and properties, such as limit laws. Here, the proof takes us through reasoning: understanding that both \(a_n\) and \(a_{n+1}\) approach the same limit, and thereby deducing that dividing the two must result in a constant ratio.

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