/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Rewrite the given expression wit... [FREE SOLUTION] | 91Ó°ÊÓ

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Rewrite the given expression without using any exponentials or logarithms. $$ \exp \left(\sqrt{\ln \left(3^{\ln (81)}\right)}\right) $$

Short Answer

Expert verified
The original expression simplifies to approximately 7.389, as \(e^2\).

Step by step solution

01

Simplify the Inner Logarithm Expression

Start with the expression inside the logarithm, \(3^{\ln(81)}\). Remember that \(81 = 3^4\), so substitute it into the expression: \(\ln(81) = \ln(3^4) = 4\ln(3)\). Thus, \(3^{\ln(81)} = 3^{4\ln(3)}\).
02

Use the Power Rule of Logarithms

Applying the power rule, \(b^{\ln(a)} = a^{\ln(b)}\), to \(3^{4\ln(3)}\), we can express it as \((3^{\ln(3)})^4 = e^4\) after applying the fact that \(3^{\ln(3)} = e\). So, \(3^{\ln(81)} = e^4\).
03

Simplify the Square Root and the Logarithm

Now substitute \(3^{\ln(81)} = e^4\) back into the expression. We find \(\sqrt{\ln(e^4)}\). Using the property \(\ln(e^x) = x\), we simplify \(\ln(e^4) = 4\). Thus, \(\sqrt{4} = 2\).
04

Remove the Exponential

Substitute the simplified result from Step 3 into \(\exp(\sqrt{4})\). The expression becomes \(\exp(2) = e^2\). Finally, express \(e^2\) without exponentials or logarithms, which is simply the number \(e^2\), but for practical purposes in this context, it is evaluated numerically as approximately 7.389.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Logarithms
Logarithms are mathematical operations that help us solve problems involving exponential growth or decay. The logarithm of a number is the power to which the base must be raised to get that number. For example, in the logarithmic expression \( \ln(a) \), \( a \) is the number, and the base is \( e \), known as Euler's number, approximately equal to 2.718. Logarithms are particularly useful for simplifying expressions involving powers and roots.
Logarithms have several properties that make them handy, such as:
  • Product Rule: \( \ln(AB) = \ln(A) + \ln(B) \)
  • Quotient Rule: \( \ln\left( \frac{A}{B} \right) = \ln(A) - \ln(B) \)
  • Power Rule: \( \ln(A^B) = B\ln(A) \)
In our expression, understanding the power rule was essential to simplify \( \ln(3^4) \) into \( 4\ln(3) \). Such properties allow us to tackle complex expressions in smaller, manageable steps.
Exponential Functions Explained
Exponentials, particularly when represented with the expression \( \exp(x) \), indicate constant growth or decay. In simple terms, \( e^x \) means the number \( e \) raised to the power of \( x \). Exponentials can describe a variety of real-world phenomena—including population growth, radioactive decay, and interest calculations.
Some critical aspects of exponentials include:
  • The base of natural logarithms, \( e \), is a special number about 2.718.
  • The inverse operation of an exponential function is a logarithm.
  • \( \exp(x) = e^x \) is commonly used, especially in scientific contexts.
Understanding how to transition from logarithms to exponentials helped us rewrite expressions like \( e^4 \) from \( 3^{\ln(81)} \), demonstrating an understanding of exponential behavior.
Applying the Power Rule
The power rule is an essential tool in both logarithms and calculus, describing how a power of a base can be manipulated when logs are involved. It tells us that \( b^{\ln(a)} = a^{\ln(b)} \), helping transform expressions into simpler or alternate forms. For instance, using \( 3^{\ln(81)} \), we found \( 81 = 3^4 \). With the power rule's insight, this becomes \((3^{\ln(3)})^4\), simplifying to \(e^4\) because \(3^{\ln(3)} = e\).
Key points about the power rule:
  • It swaps the base and the expression under the logarithm, revealing simplifications.
  • It works effectively when bases and logs interrelate, like \( a^{\ln(b)} \) to \( b^{\ln(a)} \).
This rule allows us to handle complex equations efficiently, promoting easier mathematical manipulation.
Simplification Made Easy
Simplification is the art of making math problems easier and clearer. It involves reducing expressions to their simplest form without changing values or meanings. In our example, simplifying \( \exp(\sqrt{\ln(e^4)}) \) to \( e^2 \) shows simplification in action. We broke down the initial complex expression into individual components—using known rules and properties—until we reached a basic form.
Here's a summary of how simplification works:
  • Identify and apply mathematical rules like the logarithm properties or power rules.
  • Break down complex expressions into smaller parts for calculation.
  • Perform arithmetic and substitutions carefully to avoid errors.
Simplification doesn't just solve a problem; it also reveals patterns and structures, making math more accessible and intuitive.

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Most popular questions from this chapter

Plot \(y=\exp (x)\) for \(0 \leq x \leq 2\). Let \(P(c)\) denote the point \((c, \exp (c))\) on the graph. The purpose of this exercise is to graphically explore the relationship between \(\exp (c)\) and the slope of the tangent line at \(P(c) .\) For \(c=1 / 2,1\), and \(3 / 2,\) calculate the slope \(m(c)\) of the secant line that passes through the pair of points \(P(c-0.001)\) and \(P(c+0.001) .\) For each \(c,\) calculate \(|\exp (c)-m(c)|\) to see that \(m(c)\) is a good approximation of \(\exp (c) .\) Add the three secant lines to your viewing window. For each of \(c=1 / 2,1,\) and \(3 / 2,\) add to the viewing window the line through \(P(c)\) with slope \(\exp (c)\). As we will see in Chapter \(3,\) these are the tangent lines at \(P(1 / 2), P(1)\) and \(P(3 / 2)\). It is likely that they cannot be distinguished from the secant lines in your plot.

Let \(f(x)=\cos ^{3}(x-\pi / 3) \sin (x) / x\) for \(-2 \leq x \leq 2, x \neq 0\). Locate the extreme values of the continuous extension of \(f\) to four decimal places.

An assertion is made about a function \(f\) that is defined on a closed, bounded interval. If the statement is true, explain why. Otherwise, sketch a function \(f\) that shows it is false. (Note: \(|f|\) is defined by \(|f|(x)=|f(x)| .)\) If \(f\) is continuous, then \(f^{2}\) is continuous.

A particle moves on an axis. Its position \(p(t)\) at time \(t\) is given. For a positive \(h,\) the average velocity over the time interval \([2,2+h]\) is \(\bar{v}(h)=\frac{p(2+h)-p(2)}{h}\) a. Numerically determine \(v_{0}=\lim _{h \rightarrow 0+} \bar{v}(h)\). b. How small does \(h\) need to be for \(\bar{v}(h)\) to be between \(v_{0}\) and \(v_{0}+0.1 ?\) c. How small does \(h\) need to be for \(\bar{v}(h)\) to be between \(v_{0}\) and \(v_{0}+0.01 ?\) $$ p(t)=t^{3}-8 t $$

In Exercises \(74-80\), evaluate the one-sided limits. $$ \lim _{x \rightarrow 3^{-}} \frac{x-3}{|x-3|} $$

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