Chapter 2: Problem 19
In Exercises \(17-24,\) use Theorem 2 to evaluate the limit. $$ \lim _{x \rightarrow 1}\left(x^{2}-6\right) $$
Short Answer
Expert verified
The limit is \(-5\).
Step by step solution
01
Identify the Function
The given expression is \( f(x) = x^2 - 6 \). We are asked to find \( \lim_{x \to 1} (x^2 - 6) \). This means we need to evaluate the limit of this function as \( x \) approaches 1.
02
Recognize the Type of Function
The function \( f(x) = x^2 - 6 \) is a polynomial function. According to Theorem 2, which states that the limit of a polynomial function as \( x \) approaches any number is simply the function value at that number, we can evaluate this directly.
03
Apply Theorem 2
Since the function is a polynomial, according to Theorem 2, the limit \( \lim_{x \to 1} (x^2 - 6) \) can be found by simply substituting \( x = 1 \) into the function \( f(x) = x^2 - 6 \).
04
Substitute and Calculate
Substitute \( x = 1 \) into the function: \( f(1) = 1^2 - 6 = 1 - 6 = -5 \).
05
Conclude the Evaluation
Therefore, the evaluated limit is \( -5 \). The process is complete, as this is the result of applying Theorem 2 directly to a polynomial function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Theorem 2
In calculus, **Theorem 2** is an essential rule handy for tackling limits, particularly when dealing with polynomial functions. Its beauty lies in its simplicity. The theorem essentially tells us that if we have a polynomial function and we need to find the limit as the variable approaches a particular number, we can simply substitute that number into the polynomial to find the limit. This shortcut helps us avoid lengthy calculations.For example, if you have a polynomial function like \( f(x) = a_nx^n + a_{n-1}x^{n-1} + \ldots + a_0 \) and you want to evaluate \( \lim_{x \to c} f(x) \), all you need to do is plug in \( c \) into the function:\( f(c) = a_nc^n + a_{n-1}c^{n-1} + \ldots + a_0 \).This straightforward approach is one of the reasons polynomial limits tend to be easier to solve. Remember, Theorem 2 applies specifically to polynomial functions. It tells us that such a function is continuous, meaning the limit at any point \( c \) is the same as the function value \( f \, ( \, c \, ) \), emphasizing the seamless nature of such functions over their entire domain.
Polynomial Functions
**Polynomial functions** are a fundamental class of mathematical functions, characterized by their straightforward properties and impressive versatility. These functions are expressed as sums of terms containing variables raised to non-negative integer powers, each multiplied by coefficients. A general form of a polynomial function in one variable is:\[ f(x) = a_nx^n + a_{n-1}x^{n-1} + \ldots + a_0 \]Here, \( a_n, a_{n-1}, \ldots, a_0 \) are constants, and \( n \) is a non-negative integer that indicates the highest degree of the polynomial.
- The degree of the polynomial determines the behavior and shape of its graph.
- Each term’s coefficient contributes to the height and direction of the curve.
- Polynomial functions include linear functions, quadratic functions, and higher-degree polynomials.
Limit Evaluation
When evaluating limits, especially of polynomial functions, the process can often be quite straightforward, thanks to properties like continuity and differentiability. Here are a few steps to consider for successful limit evaluation:1. **Identify the Function**: Recognize and understand the type of function you are dealing with; is it a polynomial, rational, or another type?2. **Simplify if Necessary**: Before applying any specific rules, simplify the function if it is complex, especially if it involves operations like division.3. **Apply Theorem 2**: For polynomials, use Theorem 2 directly to substitute the approaching value.4. **Substitution**: If the function is continuous at the point you're approaching, direct substitution can yield the limit immediately.For our given exercise, \( \lim_{x \to 1} (x^2 - 6) \), since it is a polynomial, direct substitution using Theorem 2 allows us to find the limit seamlessly:\( f(1) = 1^2 - 6 = -5 \).This makes it unnecessary to use more complex limit rules such as the epsilon-delta definition or L'Hôpital's Rule, thus simplifying the process for students.