/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Determine whether the sequence \... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the sequence \(\left\\{a_{n}\right\\}\) converges. If it does, state the limit. $$ a_{n}=1 / n-4^{1 / n} $$

Short Answer

Expert verified
The sequence converges to -1.

Step by step solution

01

Examine the limit of the first term

The sequence is given by \(a_n = \frac{1}{n} - 4^{1/n}\). First, examine \(\lim_{{n \to \infty}} \frac{1}{n}\). As \(n\) becomes very large, \(\frac{1}{n}\) approaches 0.
02

Examine the limit of the second term

Next, examine \(\lim_{{n \to \infty}} 4^{1/n}\). Rewrite it as \(\lim_{{n \to \infty}} e^{\ln(4)/n}\), which approaches \(e^0 = 1\) as \(n\) approaches infinity due to the exponential decay of \(\ln(4)/n\).
03

Combine the results

Now, let's combine the limits: \(\lim_{{n \to \infty}} \left(\frac{1}{n} - 4^{1/n}\right) = \lim_{{n \to \infty}} \frac{1}{n} - \lim_{{n \to \infty}} 4^{1/n} = 0 - 1 = -1\).
04

Conclusion about convergence

The sequence \(a_n = \frac{1}{n} - 4^{1/n}\) converges to \(-1\) since each part has been shown to converge separately.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit of a Sequence
In mathematics, a sequence is a set of numbers arranged in a specific order. The **limit of a sequence** refers to the value that the terms of a sequence "approach" as the index (usually denoted as \(n\)) grows infinitely large. Think of it as the target the sequence is trying to hit.
Suppose a sequence \(\{a_n\}\) approaches a particular value L as \(n\) approaches infinity, then we write \(\lim_{{n \to \infty}} a_n = L\).
Determining the limit of a sequence involves finding what value the terms will get extremely close to as \(n\) becomes very large. It's an important concept because it helps us understand the behavior of sequences at their "end."
  • If the terms settle into a particular number, the sequence has a limit.
  • If not, the sequence may oscillate or diverge, meaning it doesn't get closer to any single value.
In the exercise, we analyzed each part of the sequence \(a_n = \frac{1}{n} - 4^{1/n}\) by determining the limit of individual components to find the overall limit.
Convergent Sequence
When we say a sequence is convergent, it means that as we go along the sequence, the terms get closer and closer to a specific number, known as the limit. A **convergent sequence** is one where the terms eventually settle down around a particular number.
Mathematically, if a sequence \(\{a_n\}\) converges to a limit L, it means for any arbitrary closeness we want (called an epsilon, \(\epsilon\)), we can find a point in the sequence beyond which all terms differ from L by less than \(\epsilon\). This simply means the terms become indistinguishably close to L as \(n\) grows.
  • Having a limit suggests the sequence is well-behaved and predictable.
  • A sequence can only have one finite limit, making genuine convergence unique.
In our specific problem, after examining the limits of the sequence parts, we concluded that \(a_n = \frac{1}{n} - 4^{1/n}\) converges to \(-1\). This result indicates that as \(n\) becomes very large, the terms of the sequence hover around \(-1\).
Infinity Limit
The concept of the **infinity limit** is crucial for understanding sequences like \(\frac{1}{n}\) and \(4^{1/n}\), which are parts of our given sequence. The idea is to observe the behavior of a sequence as \(n\), the term index, grows without bound, or becomes infinitely large.
For instance:
  • The term \(\frac{1}{n}\) is well-known for approaching 0 as \(n\) increases. This happens because we're effectively distributing a single value over an increasing number of subunits.
  • Conversely, \(4^{1/n}\) behaves differently. As \(n\) increases, the exponent \(1/n\) approaches zero, transforming the term gradually into \(4^0 = 1\) due to the rules of exponentiation when raised to zero power.
By combining these observations, we acknowledged that the infinity limits of both sequence components simplified our original sequence \(a_n = \frac{1}{n} - 4^{1/n}\) to converge to \(-1\). This approach of breaking down components highlights how individual behaviors determine overall sequence furthest behavior at infinity.
Exponential Decay
**Exponential decay** is an intuitive concept where quantities decrease rapidly at a rate proportional to their current value. In sequences, it involves terms that decline as an exponent applied diminishes, like \(e^{ -kt}\) where \(k\) is positive.
Within our sequence \(a_n = \frac{1}{n} - 4^{1/n}\), the part \(4^{1/n}\) is a perfect example of exponential decay because as \(n\) increases, \(1/n\) becomes incredibly tiny, rendering \(4 ext{ raised to this term} \) close to 1. The decay is intuitive because each successive index makes the fractional exponent \(\ln(4)/n\) smaller, so its overall effect diminishes.
  • This behavior is typical of exponential models often used in natural sciences to describe declines in populations or radioactive substances.
  • Understanding this decay helps compute limits because these declining components essentially "disappear" in the presence of more stable terms.
Recognizing exponential decay thus informed how we deconstructed the sequence limit results, ensuring accurate convergence for the sequence as a whole.

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Most popular questions from this chapter

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