Chapter 1: Problem 22
Plot several points, and sketch the graph of the function defined by the given expression. $$ \operatorname{signum}\left(\left|x^{2}-x\right|\right) $$
Short Answer
Expert verified
The function is 1 for \( x \neq 0 \) and \( x \neq 1 \), and is 0 at \( x = 0 \) and \( x = 1 \).
Step by step solution
01
Understand the Signum Function
The signum function, or \( \operatorname{signum}(x) \), is a piecewise function that gives the sign of a real number. Specifically, \( \operatorname{signum}(x) = -1 \) if \( x < 0 \), \( 0 \) if \( x = 0 \), and \( 1 \) if \( x > 0 \). We will apply this to the expression \( |x^2 - x| \).
02
Examine \( |x^2 - x| \)
First, solve for when \( x^2 - x = 0 \) to understand where the absolute value expression is zero. Factoring gives \( x(x-1) = 0 \), so \( x = 0 \) or \( x = 1 \). Therefore, \( |x^2 - x| = 0 \) at these points, turning the signum function to zero at \( x = 0 \) and \( x = 1 \).
03
Determine Sign on Intervals
To find where \( x^2 - x \) is positive or negative, examine the sign of \( x(x-1) \):- For \( x < 0 \), both factors are negative, so \( x^2 - x > 0 \).- For \( 0 < x < 1 \), \( x > 0 \) and \( x-1 < 0 \), resulting in \( x^2 - x < 0 \).- For \( x > 1 \), both factors are positive, so \( x^2 - x > 0 \).
04
Apply Signum Function
For \( x < 0 \), \( x^2 - x > 0 \) so \( \operatorname{signum}(|x^2 - x|) = 1 \).For \( 0 < x < 1 \), \( x^2 - x < 0 \) but since the absolute value is non-negative, \( |x^2 - x| > 0 \) making \( \operatorname{signum}(|x^2 - x|) = 1 \).For \( x = 0 \) or \( x = 1 \), \( |x^2 - x| = 0 \), hence \( \operatorname{signum}(|x^2 - x|) = 0 \).For \( x > 1 \), \( x^2 - x > 0 \) so \( \operatorname{signum}(|x^2 - x|) = 1 \).
05
Sketch the Graph
From the previous steps, construct the graph:- For \( x < 0 \) and \( x > 1 \), graph the line \( y = 1 \).- For \( x = 0 \) and \( x = 1 \), graph the point \( y = 0 \) as a dot.- For \( 0 < x < 1 \), graph the line \( y = 1 \). This results in a horizontal line at \( y = 1 \) everywhere except at \( x = 0 \) and \( x = 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Piecewise Functions
The signum function is a classic example of a piecewise function. Piecewise functions are defined by different expressions or rules for different intervals of the domain. The signum function, denoted as \( \operatorname{signum}(x) \), specifies the sign of a real number. It can take three different values depending on the condition of \( x \):
- If \( x < 0 \), the function returns \(-1\).
- If \( x = 0 \), it returns \(0\).
- If \( x > 0 \), the function returns \(1\).
Absolute Value
The absolute value is a fundamental mathematical concept that measures the distance of a number from zero on the number line, regardless of direction. It is always non-negative. For any real number \( x \), the absolute value is represented by \( |x| \) and is defined as follows:
- \( |x| = x \) if \( x \ge 0 \)
- \( |x| = -x \) if \( x < 0 \)
Graphing Functions
Graphing functions involves plotting points or lines on a coordinate system to represent the function visually. Understanding how to graph piecewise functions like the signum function is essential:
- Identify the intervals of the function where different conditions apply.
- Determine the behavior of the function in each interval.
- Plot points or lines for each segment based on these conditions.
Quadratic Equations
Quadratic equations are polynomial equations of the form \( ax^2 + bx + c = 0 \). In the exercise, the expression \( x^2 - x \) is a simple quadratic equation, which can be solved to find the roots, an integral part of understanding the function's behavior.
- Factor the quadratic as \( x(x-1) = 0 \).
- The solutions are \( x = 0 \) and \( x = 1 \), which are the points where the quadratic expression hits zero.