Chapter 8: Problem 72
Calculate the following integrals by using the appropriate reduction formulas. $$\int(\ln x)^{2} d x$$
Short Answer
Expert verified
The simplified integral is \( x[\ln^2x-2] - 2x\ln x +2x \).
Step by step solution
01
Identify the Reduction Formula
Given that the exact function to be integrated is \((\ln x)^2\), the reduction formula for \(\int \ln^n x dx\), which says \( \int \ln^n x\, dx = x\, (\ln x^n - n) - n \int \ln^{n-1} x \, dx \) should be used.
02
Apply the Reduction Formula
Apply the reduction formula using n=2 for this integral \(\int (\ln x)^{2} d x\). This will yield \( x((\ln x)^2 - 2) - 2\int (\ln x) dx\).
03
Solve the Remaining Integral
The integral \(\int (\ln x) dx = x \ln x - x\) can be solved directly. Therefore, replace \(\int (\ln x) dx \) in the previous step with \(x \ln x - x\).
04
Simplify the Expression
Combine the expressions from the previous steps to obtain the final answer, this gives \( x[\ln^2x-2] - 2x\ln x +2x\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Reduction Formulas
Reduction formulas are a powerful tool in integral calculus. They simplify complex integral calculations, especially for functions raised to a power. By breaking down a complex problem into smaller, more manageable parts, they make the integration process more straightforward.
For example, when working with integrals of the form \( \int (\ln x)^n \, dx \), a reduction formula can help reduce the power of the function step by step. This is especially useful for calculating integrals with logarithmic expressions raised to a power.
The reduction formula for \( \int \ln^n x \, dx \) is:
\[ \int \ln^n x \, dx = x (\ln^n x - n) - n \int \ln^{n-1} x \, dx \]
In this equation, \( n \) is the power of the logarithm. By substituting and simplifying, the integral becomes more manageable.
For example, when working with integrals of the form \( \int (\ln x)^n \, dx \), a reduction formula can help reduce the power of the function step by step. This is especially useful for calculating integrals with logarithmic expressions raised to a power.
The reduction formula for \( \int \ln^n x \, dx \) is:
\[ \int \ln^n x \, dx = x (\ln^n x - n) - n \int \ln^{n-1} x \, dx \]
In this equation, \( n \) is the power of the logarithm. By substituting and simplifying, the integral becomes more manageable.
- First, break down the problem using the reduction formula.
- Apply it iteratively to reduce the power.
- Solve remaining simpler integrals.
Logarithmic Functions
Logarithmic functions are essential in mathematics, often appearing in calculus, physics, and other sciences. The logarithm, specifically the natural logarithm \( \ln x \), is the inverse of the exponential function with base \( e \).
Some important properties of \( \ln x \) include:
When integrating logarithmic functions, especially those raised to a power, understanding these properties is vital. This aids in applying techniques like reduction formulas to solve integrals more effectively.
Some important properties of \( \ln x \) include:
- \( \ln(1) = 0 \)
- \( \ln(e) = 1 \)
- \( \ln(a \cdot b) = \ln a + \ln b \)
- \( \ln\left(\frac{a}{b}\right) = \ln a - \ln b \)
- \( \ln(a^b) = b \cdot \ln a \)
When integrating logarithmic functions, especially those raised to a power, understanding these properties is vital. This aids in applying techniques like reduction formulas to solve integrals more effectively.
Indefinite Integrals
Indefinite integrals represent the antiderivative of a function, notated with the integral sign \( \int \) and lacking upper and lower limits. The result includes a constant of integration, \( C \), because the derivative of a constant is zero, making it undetectable upon differentiation.
For example, the indefinite integral of \( f(x) = \ln x \) is:
\[ \int \ln x \, dx = x \ln x - x + C \]
Indefinite integrals are crucial in various fields as they generalize the concept of an area under a curve. They can also represent quantities like displacement from a velocity function.
For example, the indefinite integral of \( f(x) = \ln x \) is:
\[ \int \ln x \, dx = x \ln x - x + C \]
Indefinite integrals are crucial in various fields as they generalize the concept of an area under a curve. They can also represent quantities like displacement from a velocity function.
- Find the antiderivative.
- Add the constant of integration \( C \).
- Check your work by differentiating.