Chapter 8: Problem 21
Calculate. $$\int x^{2}(x+1)^{9} d x$$
Short Answer
Expert verified
The short answer based on the solution is:
\(\int x^2(x+1)^9 dx = \frac{(x+1)^{12}}{12} - \frac{2(x+1)^{11}}{11} + \frac{(x+1)^{10}}{10} + C\).
Step by step solution
01
Perform substitution
Let \(u = x + 1\). We'll find \(\frac{du}{dx}\) and substitute this expression and \(u\) into the integral.
To find \(\frac{du}{dx}\), we differentiate \(u = x + 1\) with respect to \(x\):
\[\frac{du}{dx} = \frac{d}{dx}(x + 1) = 1.\]
Now we'll solve for \(dx\):
\[du = dx.\]
We must also change the integral's variable and bounds by substituting for \(u\):
\[\int x^2(x+1)^9 dx = \int (u-1)^2 u^9 du.\]
02
Expand the integrand
Before integrating, let's expand \((u-1)^2 = u^2 - 2u + 1\). Then we multiply this expression by \(u^9\) to obtain the integrand.
\[(u-1)^2 u^9 = (u^2 - 2u + 1)u^9 = u^{11} - 2u^{10} + u^9.\]
Now, we have:
\[\int (u-1)^2 u^9 du = \int (u^{11} - 2u^{10} + u^9) du.\]
03
Integrate
Now we'll integrate the expanded expression term by term:
\[\int (u^{11} - 2u^{10} + u^9) du = \int u^{11} du - 2 \int u^{10} du + \int u^9 du.\]
Using the power rule for integration, \(\int x^n dx = \frac{x^{n+1}}{n+1} + C\), we get:
\[\frac{u^{12}}{12} - \frac{2u^{11}}{11} + \frac{u^{10}}{10} + C.\]
04
Reverse substitution
Now we need to reverse the substitution by replacing \(u\) with the original variable \(x\). Recall that \(u = x + 1\), so our final answer is:
\[\frac{(x+1)^{12}}{12} - \frac{2(x+1)^{11}}{11} + \frac{(x+1)^{10}}{10} + C.\]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integral
A definite integral is a fundamental concept in calculus that represents the accumulation of quantities, often areas under a curve, over a specific interval. For example, consider the integral \[ \int_a^b f(x)\, dx \], where \( f(x) \) is the function to integrate, and \( [a, b] \) represents the interval over which we are integrating. This integral yields a numerical value representing the total 'accumulation' between \( x=a \) and \( x=b \).
Unlike indefinite integrals, which include a constant of integration \( C \), definite integrals have actual numerical limits that specify the exact region of integration. Thus, they do not include the constant of integration. The process of finding a definite integral is known as 'evaluating,' and it often involves finding the antiderivative of a function and then applying the limits of integration.
Unlike indefinite integrals, which include a constant of integration \( C \), definite integrals have actual numerical limits that specify the exact region of integration. Thus, they do not include the constant of integration. The process of finding a definite integral is known as 'evaluating,' and it often involves finding the antiderivative of a function and then applying the limits of integration.
Power Rule for Integration
The power rule for integration is a quick and efficient method for integrating polynomials. It states that when you are integrating a function of the form \( x^n \), the antiderivative is given by \( \frac{x^{n+1}}{n+1} \), as long as \( n eq -1 \). To apply the power rule:
- Increment the exponent \( n \) by 1 to get \( n+1 \).
- Divide the entire term by the new exponent, \( n+1 \).
- Add the constant of integration \( C \) at the end of the process if you are finding an indefinite integral.
U-Substitution
U-substitution is a technique used to simplify complex integrals by changing the variable of integration to something more manageable. It is especially useful when the integrand is a product of functions or when it involves a composition of functions. To perform a u-substitution:
- Choose a part of the integrand to be \( u \) such that its derivative \( du \) appears somewhere in the integral, at least up to a constant factor.
- Calculate \( du \), which is the derivative of \( u \) with respect to \( x \).
- Express \( dx \) in terms of \( du \), if necessary.
- Rewrite the entire integral in terms of \( u \) and \( du \).
- Perform the integration with respect to \( u \).
- Finally, substitute back the original variable to express the antiderivative in terms of \( x \).
Polynomial Integration
Polynomial integration relates to the process of integrating polynomial functions. A polynomial function is made up of terms in the form of \( ax^n \) where \( a \) is a coefficient and \( n \) is a non-negative integer exponent. The steps for integrating a polynomial by term are:
- Identify each term in the polynomial that is in the form of \( ax^n \).
- Apply the power rule for integration to each term as described above.
- Add up the integrated terms to find the antiderivative of the entire polynomial.
- If you are performing a definite integral, evaluate the antiderivative at the upper and lower limits of the interval and take their difference.