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Calculate. \(\int x e^{x^{2}} d x\).

Short Answer

Expert verified
The short answer is: \(\int x e^{x^2} dx = x e^{x^2} + C\)

Step by step solution

01

Choose a substitution

We can choose the substitution: \(u = x^2\) Now let's find the derivative of \(u\) with respect to \(x\): \(\frac{d u}{d x} = \frac{d}{d x}(x^2) = 2x\)
02

Solve for dx

Next, we will solve for \(dx\) in terms of \(du\): \(dx = \frac{du}{2x}\)
03

Rewrite the integral in terms of u

Now we rewrite the integral in terms of \(u\): \(\int x e^{x^2} dx = \int e^u \frac{du}{2x}\) Notice that there is still an \(x\) in the integral. We can rewrite it in terms of \(u\) using the substitution equation from Step 1: \(x = \sqrt{u}\) So the integral becomes: \(\int e^u \frac{du}{2\sqrt{u}}\)
04

Simplify the integral

We can simplify this integral further by canceling out the constant and rearranging: \(\int e^u \frac{du}{2\sqrt{u}} = \frac{1}{2} \int \frac{e^u}{\sqrt{u}} du\)
05

Integrate with respect to u

Now we can integrate with respect to \(u\): \(\frac{1}{2} \int \frac{e^u}{\sqrt{u}} du = \frac{1}{2} \cdot 2 \sqrt{u} e^u + C\) Where \(C\) is the constant of integration.
06

Substitute back in terms of x

Finally, we substitute back the original variable \(x\) using the substitution equation from Step 1: \(\frac{1}{2} \cdot 2 \sqrt{u} e^u + C = \sqrt{x^2} e^{x^2} + C = x e^{x^2} + C\) So the integral of the given function is: \(\int x e^{x^2} dx = x e^{x^2} + C\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

u-substitution
The technique of u-substitution is widely employed in integral calculus to simplify the process of finding indefinite integrals. It involves a change of variable that transforms a complicated integral into a simpler one, which is easier to evaluate. The process is analogous to a change of coordinates in geometry, where a problem becomes easier to solve in a different coordinate system.

For instance, in the exercise \( \int x e^{x^{2}} dx \), we set \( u = x^2 \) as the substitution. Then we differentiate \( u \) with respect to \( x \) to find \( \frac{du}{dx} \) and subsequently solve for \( dx \). This allows us to rewrite the original integral in terms of \( u \), which simplifies the integration process. Understanding when and how to apply u-substitution comes with practice and can significantly increase the efficiency in solving integrals.
Indefinite Integrals
Indefinite integrals, also known as antiderivatives, are a fundamental concept in the study of integral calculus. An indefinite integral represents a family of functions whose derivatives are equal to the original function being integrated. Indefinite integrals are often accompanied by a constant of integration, denoted by \( C \), because when differentiating, constants become zero and, therefore, the antiderivative is not unique.

In the context of our exercise, once we apply u-substitution, we integrate with respect to \( u \) to yield the indefinite integral, which in this case is expressed as \( \frac{1}{2} \cdot 2 \sqrt{u} e^u + C \). The \( + C \) signifies that there can be any constant added to the antiderivative that would not alter the derivative back to the original function.
Integral Calculus
Integral calculus is one of the two principal branches of calculus, with the other being differential calculus. It primarily deals with the concept of integration, which is the mathematical process of finding the area under a curve or, more generally, finding the accumulated quantity, such as total growth or displacement, that corresponds to a distributed rate of change such as density or velocity.

Within this framework, integral calculus encompasses a range of techniques for evaluating integrals, of which u-substitution is just one. Integral calculus is not only concerned with the computation of these integrals but also with understanding the relationships between functions and their antiderivatives, which is crucial for solving real-world problems involving accumulation and area.
Exponential Functions
Exponential functions are a class of mathematical functions characterized by an exponent that is a variable. These functions are commonly written in the form \( e^x \) where \( e \) is the base of the natural logarithm, approximately equal to 2.71828. Exponential functions arise in various applications such as compound interest, population growth models, and radioactive decay, due to their defining property of having a rate of change proportional to the function's current value.

In our integration example, \( e^{x^{2}} \) is an exponential function wherein the exponent is another function, \( x^2 \) in this case. When integrating exponential functions, especially when involved in composite functions as seen in the exercise, it's common to use methods like u-substitution to simplify integration. Understanding the behavior of exponential functions and their integrals can illuminate complex phenomena across natural and social sciences.

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