Chapter 7: Problem 18
Show that $$\tanh ^{-1} x=\frac{1}{2} \ln \left(\frac{1+x}{1-x}\right)
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Chapter 7: Problem 18
Show that $$\tanh ^{-1} x=\frac{1}{2} \ln \left(\frac{1+x}{1-x}\right)
\cdot-1
These are the key concepts you need to understand to accurately answer the question.
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