Chapter 5: Problem 13
Exercise 12 taking \(f(x)=-3 x\).
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Chapter 5: Problem 13
Exercise 12 taking \(f(x)=-3 x\).
These are the key concepts you need to understand to accurately answer the question.
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Let \(f(x)=x^{3}-x \quad \therefore |\) for \(x \in[-1,2]\) (a) Find the average value of \(f\) on this interval. (b) Estimate with three decimal place accuracy a number \(c\) in the interval at which \(f\) takes on its average value. (c) Use a graphing utility to illustrate your results with a figure similar to Figure \(5.9 .2 .\)
Reverse the roles of \(x\) and \(u\) in \((5.7 .2)\) and write $$\int_{x(a)}^{x(b)} f(x) d x=\int_{a}^{b} f(x(u)) x^{\prime}(u) d u$$ (The area of a circular region) The circle \(x^{2}+y^{2}=r^{2}\) encloses a circular disc of radius \(r\). Justify the familiar formula \(\therefore=\pi r^{2}\) by integration. HINT: The quarter-disk in the first quadrant is the region below the curve \(y=\sqrt{r^{2} - x^{2}}, x \in\) [0,\(r\) ]. Therefore $$A=4 \int_{0}^{r} \sqrt{r^{2}-x^{2}} d x$$ Set \(x=r \sin u, d x=r \cos u d u\).
A rod 6 meters long is placed on the \(x\) -axis from \(x=0\) to \(x=6 .\) The mass density is \(12 / \sqrt{x+1}\) kilograms per meter. (a) Find the mass of the rod and the center of mass. (b) What is the average mass density of the rod?
Calculate. $$\int \frac{\sec ^{2} x}{\sqrt{1+\tan x}} d x$$
Reverse the roles of \(x\) and \(u\) in \((5.7 .2)\) and write $$\int_{x(a)}^{x(b)} f(x) d x=\int_{a}^{b} f(x(u)) x^{\prime}(u) d u$$ Find the area enclosed by the ellipse \(b^{2} x^{2}+a^{2} y^{2}=a^{2} b^{2}\).
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