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An object moves along a coordinate line, its position al each time \(t \geq 0\) given by \(x(t)\). Find the position, velocity, and acceleration at time \(t_{0} .\) What is the speed at time \(t_{0} ?\) $$x(t)=5 t-t^{3} ; \quad t_{0}=3$$.

Short Answer

Expert verified
At \(t_{0} = 3\), the position is 6, velocity is -22, acceleration is -18 and the speed is 22.

Step by step solution

01

Find the position

The position at time \(t_{0} = 3\) can be found by substituting 3 into the equation for \(x(t)\). It will be \(x(3) = 5(3) - (3)^3 = 6\).
02

Find the velocity

The first derivative of \(x(t)\) will give the velocity function. The derivative of \(x(t) = 5t - t^3\) is \(v(t) = 5 - 3t^2\). Substituting \(t_{0} = 3\): \(v(3) = 5 - 3(3)^2 = -22\). This signifies that the object is moving in the negative direction at \(t_{0} = 3\).
03

Find the acceleration

The second derivative of \(x(t)\) will give the acceleration function. The derivative of \(v(t) = 5 - 3t^2\) is \(a(t) = -6t\). Substituting \(t_{0} = 3\): \(a(3) = -6(3) = -18\). This signifies that the object is accelerating in the negative direction at \(t_{0} = 3\).
04

Find the speed

The speed is simply the absolute value of the velocity. So the speed at \(t_{0} = 3\) is \(|v(3)| = |-22| = 22\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Position Function
In the context of motion along a coordinate line, the position function, often denoted as x(t), represents the location of an object at any given time t. Think of it as a snapshot of where something is at a specific moment. It’s the starting point for understanding the object's motion.

For example, the exercise provided uses the position function x(t) = 5t - t^3, where t represents time. By setting t to any value, we can find out where the object will be at that time. Specifically, at time t_0 = 3, we substitute the value into the function to get the object's position: x(3) = 5(3) - (3)^3 = 15 - 27 = 6. So at t = 3 seconds, the object is at the position 6 on the coordinate line.
Velocity in Calculus
Moving beyond position, velocity in calculus represents how fast an object's position is changing over time. It is the first derivative of the position function with respect to time, and it provides a sense of direction (forward or backward) and speed of movement.

In calculus, finding the velocity function involves differentiating the position function. From our exercise, differentiating x(t) = 5t - t^3 gives us the velocity function v(t) = 5 - 3t^2. This tells us how the velocity of the object changes as time progresses. If we want to find the velocity at time t_0 = 3, we simply substitute 3 into v(t), yielding v(3) = 5 - 3(3)^2 = -22. A negative sign here indicates that the object is moving in the opposite direction of the positive coordinate axis.
Acceleration in Calculus
Acceleration in calculus is all about the change in velocity over time. Just like velocity is the first derivative of position, acceleration is the first derivative of velocity or, equivalently, the second derivative of position.

When it comes to our exercise, we obtain the acceleration by differentiating the velocity function v(t) = 5 - 3t^2 to get a(t) = -6t. This acceleration function depicts how the object's velocity changes at different times. Substituting time t_0 = 3 into the acceleration function a(t), we find out that the acceleration at that moment is a(3) = -6(3) = -18. A negative value for acceleration suggests that the object is slowing down in the direction of the positive coordinate axis or speeding up in the opposite direction.
Speed and Velocity
Students often confuse speed with velocity, but they're not the same in physics. Velocity is a vector quantity, meaning it has both magnitude and direction, while speed is a scalar—it only has magnitude. In simple terms, speed tells us how fast an object is moving regardless of its moving direction.

In the exercise, the velocity at t_0 = 3 is -22 units per second, which includes the direction (indicated by the negative sign). However, when we talk about speed, we are interested in the absolute value of this number, without care for direction. So, we take the absolute value of the velocity to find the speed at t_0 = 3, which is |v(3)| = |-22| = 22 units per second. This tells us how fast the object is moving, but not its direction of motion.

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