Chapter 3: Problem 38
Find \(d^{3} y / d x^{3}\). $$y=\frac{x^{4}+2}{x}$$
Short Answer
Expert verified
So, the third derivative of the function \(y=\frac{x^{4}+2}{x}\) is \(y''' = 6 - 12x^{-4}\).
Step by step solution
01
Rewrite the Function
The function is rewritten in the form of \(y=x^{3}+\frac{2}{x}\) . This form simplifies the task of differentiation.
02
First Differentiation
The Power Rule of differentiation and the Chain Rule are applied for the first differentiation: \[y' = \frac{d}{dx}(x^3) + \frac{d}{dx}(2/x) = 3x^{2} - 2x^{-2}\]
03
Second Differentiation
The Power Rule of differentiation and the Chain Rule are applied again for the second differentiation: \[y'' = \frac{d}{dx}(3x^{2}) + \frac{d}{dx}(- 2x^{-2}) = 6x + 4x^{-3}\]
04
Third Differentiation
The Power Rule of differentiation and the Chain Rule are applied once more for the third differentiation: \[y''' = \frac{d}{dx}(6x) + \frac{d}{dx}(4x^{-3}) = 6 - 12x^{-4}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
To begin mastering differentiation, especially when dealing with higher-order derivatives, the power rule is your essential tool. This rule helps us find the derivative of functions with terms like \(x^n\). The basic premise of the power rule is straightforward: if you have a power of \(x\) in your function, \(x^n\), its derivative is found by bringing down the power \(n\) as a coefficient and reducing the power by one. In mathematical terms, this is:
Let's see it in action with our problem. Starting from \(y = x^3 + \frac{2}{x}\), use the power rule:
- \( \frac{d}{dx}(x^n) = nx^{n-1} \)
Let's see it in action with our problem. Starting from \(y = x^3 + \frac{2}{x}\), use the power rule:
- For \(x^3\), the derivative is \(3x^2\).
- For \(\frac{2}{x} = 2x^{-1}\), the derivative is \(-2x^{-2}\).
Chain Rule
Another valuable technique in differentiation is the chain rule. This rule is essential when dealing with composite functions - functions within functions. The chain rule helps us differentiate each part of the composite function systematically.
In simple terms, when you have a function \(h(x)\) expressed as \(f(g(x))\), the derivative is computed as:
Although the chain rule is not overtly explicit in our problem, it's subtly present. Consider the term \(2x^{-1}\) from the rewritten function \(y= x^3 + \frac{2}{x}\). Since we are dealing with a negative exponent (\(x^{-1}\)), we treat this as a composite function and differentiate accordingly:
In simple terms, when you have a function \(h(x)\) expressed as \(f(g(x))\), the derivative is computed as:
- \( h'(x) = f'(g(x)) \cdot g'(x) \)
Although the chain rule is not overtly explicit in our problem, it's subtly present. Consider the term \(2x^{-1}\) from the rewritten function \(y= x^3 + \frac{2}{x}\). Since we are dealing with a negative exponent (\(x^{-1}\)), we treat this as a composite function and differentiate accordingly:
- Differentiate the outer function 2 multipliers as \(-(2) \cdot (-1) \cdot x^{-2}\), giving us \(-2x^{-2}\).
Differentiation Techniques
Differentiation techniques are methods that allow us to tackle functions of varying complexity when finding their derivatives, especially useful in higher-order derivatives.
In the exercise of finding \( \frac{d^3y}{dx^3} \) from the function \( y = \frac{x^4 + 2}{x} \), multiple differentiation techniques come into play.
In the exercise of finding \( \frac{d^3y}{dx^3} \) from the function \( y = \frac{x^4 + 2}{x} \), multiple differentiation techniques come into play.
- **Rewriting**: Simplifying the expression into \( y = x^3 + \frac{2}{x} \) allows for straightforward application of the power rule and chain rule.
- **Sequential application**: Differentiation doesn’t happen all at once; it occurs through repeated application of rules, calculating one derivative, then the next, adapting each step.
- **Attention to detail**: In higher-order derivatives, signs and powers are crucial, where each step relies on the precision of the previous.