Chapter 12: Problem 20
Expand \(f(x)\) in powers of \(x\) $$f(x)=\left(x^{2}+x\right) \ln (1+x)$$
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Chapter 12: Problem 20
Expand \(f(x)\) in powers of \(x\) $$f(x)=\left(x^{2}+x\right) \ln (1+x)$$
These are the key concepts you need to understand to accurately answer the question.
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Derive a series expansion in \(x\) for the function and specify the numbers \(x\) for which the expansion is valid. Take \(a>0\). $$f(x)=\cos a x$$
Sct \(f(x)=\cos x\) (a) Find the Taylor polynomial \(P_{n}\) for \(f\) of least degree that approximates \(\cos x\) at \(x=\pi / 30\) with three decimal place accuracy, Then use that polynomial to obtain an estimate of \(\cos (\pi / 30)\). (b) Find the Taylor polynomial \(P_{n}\) for \(f\) of least degree that approximates \(\cos x^{\circ}\) at \(x=9\) with four decimal place ac curacy. Then use that polynomial! : o obtain an estimate of \(\cos 9^{\circ}\)
Derive a series expansion in \(x\) for the function and specify the numbers \(x\) for which the expansion is valid. Take \(a>0\). $$f(x) \equiv \sin a x$$
Consider the following sequence of steps. First, take the unit interval [0,1] and delete the open interval \(\left(\frac{1}{3} \cdot \frac{2}{3}\right) .\) Next, delete the two open intervals \(\left(\frac{1}{8}, \frac{2}{9}\right)\) and \(\left(\frac{7}{8}, \frac{8}{9}\right)\) from the two intervals that remain after the first step. For the third step, delete the middle thirds from the four intervals that remain after the second step. Continue on in this manner. What is the sum of the lengths of the intervals that have been deleted? The set that remains after all of the "middle thirds" have been de'cted is called line Cantor middle third set. Give some points that arc in the Cantor set.
Let \(\sum a_{k} x^{k}\) be a series with radius of convergence \(r>0\) (a) Show that if the series is absolutely convergent at one endpoint of its interval of convergence, then it is absolutely convergent at the other endpoint. (b) Show that if the interval of convergence is \((-r . r)\) then the series is only conditionally convergent at \(r\)
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