Chapter 10: Problem 6
Express the curve by an equation in \(x\) and \(y\). $$x(t)=\sec ^{2} t, \quad y(t)=2+\tan t$$
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Chapter 10: Problem 6
Express the curve by an equation in \(x\) and \(y\). $$x(t)=\sec ^{2} t, \quad y(t)=2+\tan t$$
These are the key concepts you need to understand to accurately answer the question.
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Find the length of the curve \(y=x^{2 / 3}, x \in[1,8] .\) HiNT: Work with the mirror image \(y\) =\(x^{3 / 2}, x \in[1,4]\)
Use this method to find the point(s) of self-intersection of each of the following curves. $$x(t)=\sin 2 \pi t, \quad y(t)=2 t-t^{2} \quad 1 \subset[0,4]$$
Find the points \((x, y)\) at which the curve has: (a) a horizontal tangent: (b) a vertical tangent. Then sketch the curve. $$x(t)=3 t-t^{3}, \quad y(t)=t+1$$
Determine the eccentricity of the ellipse. $$(x-1)^{2} / 25+(y+2)^{2} / 9=1$$
Show that the curve \(y=\cosh x\) has the property that for every interval \([a, b]\) the length of the curve from \(x=a\) to \(x=b\) equals the area under the curve from \(x=a\) to \(x=b\).
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