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Find the number(s) \(x\) in the interval \([0.2 \pi]\) which satisfy the equation. $$\tan x / 2=1$$.

Short Answer

Expert verified
The number \(x\) in the interval [0, \(2\pi\)] that satisfies the equation \(\tan (x / 2) = 1\) is \(x=\(\pi/2\).

Step by step solution

01

Basic Understanding

The given function is \(\tan (x / 2) = 1\). We need to find \(x\) such that its value lies in the interval [0, \(2\pi\)]. Let's start by finding when the tangent function equals 1. Note, the period of the tangent function is \(\pi\), comparing this with function we know that \(\tan^{-1}(1) = \(\pi/4\).
02

Determining the Value

Because the equation inside the tangent function is \(x/2\), we need to adjust the value to fit this. We set \(x/2 = \(\pi/4\). Solving for \(x\) gives \(x = \(\pi/2\).
03

Validating the Answer

Let's validate whether the answer meets initial criteria. The found value \(x=\(\pi/2\) is indeed in the range [0, \(2\pi\)] and thus, it is the valid solution

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