Chapter 1: Problem 9
Prove that if \(a, b\) are strictly positive integers then $$ \frac{a^{2}}{b^{2}}<2 \Rightarrow \frac{(a+2 b)^{2}}{(a+b)^{2}}<2 $$ Prove, moreover, that $$ \frac{(a+2 b)^{2}}{(a+b)^{2}}-2<2-\frac{a^{2}}{b^{2}} $$ This means that \(\frac{(a+2 b)^{2}}{(a+b)^{2}}\) is closer to 2 than \(\frac{a^{2}}{b^{2}}\) is.
Short Answer
Step by step solution
Start with the Given Inequality
Setup the Expression for Transformation
Formulate the New Inequality
Simplify the Inequality Further
Analyze the Difference of Inequalities
Compare the Expressions
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Strictly Positive Integers
Transformation of Expressions
- Multiply both sides by \( b^2 \) to avoid the fraction: \( a^2 < 2b^2 \).
- Apply algebraic techniques to manipulate expressions, like expanding or factoring polynomials.
Cross-Multiplication
- Multiply every component of the inequality by the denominator: \( a^2 + 4ab + 4b^2 < 2(a^2 + 2ab + b^2) \).
- This step allows us to directly compare the simplified expressions without the interference of fractions.
Mathematical Simplification
- To prove \( \frac{(a+2b)^2}{(a+b)^2} < 2 \), we simplified expressions until we reached \( 2b^2 < a^2 \), which provided contradictions against initial assumptions, resetting the proof trajectory.
- Mathematical simplification allows one to efficiently isolate variables and reduce equations to manageable forms, aiding in process understanding and error-avoidance.